Answer:
After 2 seconds
Step-by-step explanation:
First step is find an equation of velocity:
h(t)=-16t2+64t+112. The velocity function is derivated from position function, so we should do that.
v(t)= h´(t)= -16*2*t+64 ⇒ v(t)= -32t+64.
Now we know the arrow reach the maximun height when this velocity is equal to zero when t>0.
0=-32t+64 ⇒ 32t=64, split each member for 32 ⇒ 
=
t=2. That means after 2 sec. the arrow reach the maximum height
8 Is the unit rate. For 9/27
Y = e^tanx - 2
To find at which point it crosses x axis we state that y= 0
e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061
to find slope at that point first we need to find first derivative of funtion y.
y' = (e^tanx)*1/cos^2(x)
now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
3/4 is as simple as it gets 5/10- 1/2
The equation of the parent square root function to represent the equation of the graphed function will be, y=√x-2
According to the statement
we have to show the square root function as a equation in the graphical representation.
So,
we know that the definition of a
Graph a diagram showing the relation between variable quantities, typically of two variables and it also show the relation between more than two variables.
Now, we know that the definition of Equation is a mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.
And the equation obtained from the graph is a y=√x-2 by a some calculations in the graph.
So, The equation of the parent square root function to represent the equation of the graphed function will be, y=√x-2
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