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Rus_ich [418]
2 years ago
7

PLEASE HELP FAST X= Y= Find value of missing variable

Mathematics
1 answer:
AfilCa [17]2 years ago
8 0

Step-by-step explanation:

hope u understand......

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Write A number d minus 2 is less than -1 as an inequality
laiz [17]

Answer:

d-2 < -1

Step-by-step explanation:

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3 years ago
What is the answer? I'll give branliest
Katena32 [7]

Answer:

a

Step-by-step explanation:

8 0
3 years ago
Please help me with this geometry question. x and pr needed ao basically like this x=(answer), PR=(answer). Thank you
Dennis_Churaev [7]

Answer:

x = -1, PR = 38.

Step-by-step explanation:

As Q is the midpoint of PR

PQ = QR

6x + 25 = 16 - 3x

9x = -9

x = -1.

PR

= 6x + 25 + 16 - 3x

= 6(-1) + 25 + 16 - 3(-1)

= -6 + 25 + 16 + 3

= 38.

7 0
2 years ago
The slope line that passes through -3/5 and 4,1
irakobra [83]

Answer:1

Step-by-step explanation:

8 0
3 years ago
You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o
Aleksandr [31]

Answer:

Therefore the circumference of the circle is =\frac{20\pi}{4+\pi}

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

\Rightarrow s=\frac{10-\pi r}{2}

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

A=\pi r^2+ (\frac{10-\pi r}{2})^2

\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2

\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}

\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25

For maximum or minimum \frac{dA}{dr}=0

Differentiating with respect to r

\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi

Again differentiating with respect to r

\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}    > 0

For maximum or minimum

\frac{dA}{dr}=0

\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0

\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}

\Rightarrow r=\frac{10}{4+\pi}

\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0

Therefore at r=\frac{10}{4+\pi}  , A is minimum.

Therefore the circumference of the circle is

=2 \pi \frac{10}{4+\pi}

=\frac{20\pi}{4+\pi}

4 0
2 years ago
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