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3 years ago

Find the 60th term of the arithmetic sequence −29,−49,−69,...

Mathematics

1 answer:

andreev551 [17]3 years ago

6 0

Answer:

Step-by-step explanation:

it is basically counting by 2s but rather by 20s.

20, 40,60,80

all you do is add a 9 at the end.

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What is the solution for the inequality y > |2x-3| +1?

liubo4ka [24]

1/2x-3................

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3 years ago

If an object is dropped from a height of 116, the function h(t)=-16t^2+116 gives the height of the object after t seconds. When

Natasha_Volkova [10]

Answer:

Step-by-step explanation:

To find how long it takes for the object to hit the ground you need to set h(t)=0 after this you need to find the number that when plugged into t makes the equation equal to 0

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3 years ago

Please help me it is division problems

Alexxx [7]

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2 years ago

A ribbon is 30cm long and it is cut into three pieces such that each piece is 2cm longer than the next. Represent this as an equ

Alisiya [41]

Answer:

Step-by-step explanation:

3 pieces such that each piece is 2 cm longer then the next...

x , x + 2, x + 4

x + x + 2 + x + 4 = 30

3x + 6 = 30

3x = 30 - 6

3x = 24

x = 24/3

x = 8

x + 2 = 8 + 2 = 10

x + 4 = 8 + 4 = 12

check...

8 + 10 + 12 = 30

18 + 12 = 30

30 = 30 (correct)...it checks out

the ribbon lengths are : 8 cm, 10 cm, and 12 cm

3 0

3 years ago

Read 2 more answers

Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.

NISA [10]

Answer:

$\frac{\sqrt{\pi}}{4}$

Step-by-step explanation:

You are going to integrate the following function:

$g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}$ (1)

furthermore, you know that:

$\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}$

lets call to this integral, the integral Io.

for a general form of I you have In:

$I_n=\int_0^{\infty}x^ne^{-ax^2}dx$

furthermore you use the fact that:

$I_n=-\frac{\partial I_{n-2}}{\partial a}$

by using this last expression in an iterative way you obtain the following:

$\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}}$ (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

$\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}$

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2 years ago

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