Use distributive property. 4 x 63 = ??

NNEED HELP!! GEETSS BRAINLIEST**

sergejj [24]

Answer:

D. $y=3\cos \left(\dfrac{4}{3}x-2\pi\right)+2$

Step-by-step explanation:

The period of the functions $y=\cos x,\ y=\sin x$ is $2\pi.$

The period of the function $y=a\cos (kx+b),\ y=a\sin(kx+b)$ is ALWAYS $\dfrac{2\pi}{k}$

In your case, you have function $y=-3\sin \left(\dfrac{2}{3}x-2\pi \right)+2$ and this function has the period

$\dfrac{2\pi}{\dfrac{2}{3}}=3\pi.$

You need to find the function that will have the period that is half of $3\pi,$ so

$\dfrac{3\pi}{2}=\dfrac{2\pi}{k}\\ \\3k=4\\ \\k=\dfrac{4}{3}.$

So, correct choice is

$y=3\cos \left(\dfrac{4}{3}x-2\pi\right)+2$

7 0

3 years ago

Read 2 more answers

According to a survey, 60 % of the residents of a city oppose a downtown casino. Of these 60 % about 8 out of 10 strongly opp

katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

Step-by-step explanation:

(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino.

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

Probability that a radomly selected resident opposes the casino: P(A)

Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the probability that a radomly selected resident opposes the casino, P(A)

Probability = number of favorable outcomes / number of possible outcomes

P(A) is given as 60%, which in decimal form is 0.60

ii) Next, determine,the probability that a resident who opposes the casino strongly opposes it, P(B/A):

It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or intersection: P(A∩B).

So, you can use the definition of conditional probability:

P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

P(A∩B) = P(B/A)×P(A) = (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that a radomly selected resident who opposes the casino does strongly oppose the casino, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

8 0

3 years ago

Why can't <img src="https://tex.z-dn.net/?f=x%5E2-5x-1" id="TexFormula1" title="x^2-5x-1" alt="x^2-5x-1" align="absmiddle" class

7nadin3 [17]

Answer:

Step-by-step explanation:

Discussion.

Not directly. But the quadratic formula can do it. But that's not your question.

the factors you get must contain the factors for 1 which are 1 and - 1

These factors must add to - 5. There's no way that will happen with 1 and - 1 and you would be creative math if you tried to say that you could make one of the factors (x -1-1-1-1-1-1). That creates a whole new question.

5 0

1 year ago

(4p2 - 5p - 4) + (5p2 - 4-2p)

Rasek [7]

Answer:

9p^2 - 7p - 8

Hope this helps! Can I have BRAINLIEST please?

5 0

3 years ago

Read 2 more answers

Hailey bought 3 pounds of apples for $7.70. How much did she pay per pound?

7nadin3 [17]