Costs<span> $.59c(p) = .59p. C(p) has unit $/lbs, </span>p=<span>lbs</span>
Answer:
A sample of 1068 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?
We need a sample of n.
n is found when M = 0.03.
We have no prior estimate of , so we use the worst case scenario, which is 
Then
Rounding up
A sample of 1068 is needed.
Answer:
180°
Step-by-step explanation:
∠LMN = 90° and is the angle in a semicircle, thus
LN is the diameter of the circle and the measure of arc LPN is
m arc LPN = 180°
Answer:
{f(x) | -∞ < f(x) ≤ 4 }
Step-by-step explanation:
The range is made up of the y values. Remember f(x) = y
In this graph the least value of y is -∞ and the greatest value of y is 4
So, the range is {f(x) | -∞ < f(x) ≤ 4 } which is the 2nd choice
