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SIZIF [17.4K]
3 years ago
9

The product of the slopes of perpendicular lines is ?1. Which function represents a line that is perpendicular to y = ?6x + 7? A

) y = 6x + 2 B) y = 1 6 x + 4 C) y = ?x ?3 D) y = ? 1 6 x + 7
Mathematics
1 answer:
Roman55 [17]3 years ago
7 0

Answer:

The correct answer is B) y = 1/6x + 4

Step-by-step explanation:

Since the slope of the original line is -6, we are looking for a line with a slope of 1/6. This is because perpendicular lines have opposite and reciprocal slopes. B is the only answer that satisfies that situation.

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Multiply and find the total<br><br> Algebra
fomenos

Answer:

n - 1

Step-by-step explanation:

(n-1)(n-5) / 2(n+3) ×2(n+3) / (n-5)

Kindly check attached picture for simplification

6 0
2 years ago
Monica’s retirement party cost two dollars, plus an additional three dollars for every guess she invites. If there are 16 guests
lesya692 [45]

Answer:

TWO BUCKS?? ballin on a budget

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8 0
2 years ago
Which statement is true regarding the graphed functions?
padilas [110]

Answer:

C

Step-by-step explanation:

You can look them up in the graphs.

f(2) means "where is the blue graph when x=2?", and you can see it is at y=0.

4 0
2 years ago
Read 2 more answers
Question 1
enyata [817]

Answer:

x = 1/8

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

8 0
2 years ago
Polygon F has an area of 36 square units. Aimar drew a scaled version of Polygon F and labeled it Polygon G. Polygon G has an ar
Free_Kalibri [48]

Answer:

1/3

Step-by-step explanation:

The area of Polygon GGG is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF.

Each side of Polygon FFF was multiplied by a certain value, known as the scale factor , to result in an area that is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF.

[Show me an example of how scale factor affects area]

\dfrac1{10}  

start fraction, 1, divided by, 10, end fraction

 

 

\begin{aligned} A &= \left(l\times\dfrac1{10}\right)\times\left(w\times\dfrac1{10}\right) \\ \\ A&= l\times w\times\dfrac1{10}\times\dfrac1{10} \\ \\ A&= lw \times \left(\dfrac1{10}\right)^2\end{aligned}  

 

 

 

 

 

 

 

 

\dfrac1{10}  

start fraction, 1, divided by, 10, end fraction\left(\dfrac1{10}\right)^2  

 

left parenthesis, start fraction, 1, divided by, 10, end fraction, right parenthesis, start superscript, 2, end superscript

Hint #22 / 3

The area of a polygon created with a scale factor of \dfrac1x  

x

1

​  start fraction, 1, divided by, x, end fraction has \left(\dfrac1{x}\right)^2(  

x

1

​  )  

2

left parenthesis, start fraction, 1, divided by, x, end fraction, right parenthesis, start superscript, 2, end superscript the area of the original polygon:

\left(\text{scale factor}\right)^2=\text{fraction of the area the scale copy has}(scale factor)  

2

=fraction of the area the scale copy hasleft parenthesis, s, c, a, l, e, space, f, a, c, t, o, r, right parenthesis, start superscript, 2, end superscript, equals, f, r, a, c, t, i, o, n, space, o, f, space, t, h, e, space, a, r, e, a, space, t, h, e, space, s, c, a, l, e, space, c, o, p, y, space, h, a, s

The area of Polygon GGG is \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction the area of Polygon FFF. Let's substitute \dfrac19  

9

1

​  start fraction, 1, divided by, 9, end fraction into the equation to find the scale factor.

\left(\dfrac1{?}\right)^2=\dfrac19(  

?

1

​  )  

2

=  

9

1

​  left parenthesis, start fraction, 1, divided by, question mark, end fraction, right parenthesis, start superscript, 2, end superscript, equals, start fraction, 1, divided by, 9, end fraction

The scale factor is \dfrac13  

3

1

​  start fraction, 1, divided by, 3, end fraction.

Hint #33 / 3

Aimar used a scale factor of \dfrac13  

3

1

​  start fraction, 1, divided by, 3, end fraction to go from Polygon FFF to Polygon GGG.

4 0
2 years ago
Read 2 more answers
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