Answer:
(f+g)(x) = 60x + 400
Step-by-step explanation:
Given :
Amount in account A:
f(x) = 20x + 100
Amount in account B :
g(x) = 40x + 300
Total amount in Account A and B:
f(x) + g(x) = (20x + 100) + (40x + 300)
(f+g)(x) = (20x + 40x) + (100 + 300)
(f+g)(x) = 60x + 400
Answer:
Therefore the length of QP = 3.4 units
Step-by-step explanation:
Given:
PQ = 2x + 1
XF = 7x - 4
PF = x
Q is the mid poimt of XF
∴ XQ = QF
QF = PQ - PF ..........( Q - F - P )
= 2x + 1 - x
∴ QF = x + 1
∴ XQ = QF = x + 1
TO Find:
QP = ?
Solution:
By Addition Property we have
Substituting the given values in above equation we get
(7x - 4) + x = (x +1) + (x +1) + x
8x -4 = 3x +2
8x - 3x + 4 + 2
5x = 6
∴
Now we require
QP = (2x + 1)
∴
Therefore the length of QP = 3.4 units
