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Inessa05 [86]
2 years ago
5

Find the first 4 terms of: Σ () N=1 (9 n - 6). Help please

Mathematics
1 answer:
Hunter-Best [27]2 years ago
7 0

A1 = 9 × 1 - 6 = 3

A2 = 18 - 6 = 12

A3 = 27 - 6 = 21

A4 = 36 - 6 = 30.

Step-by-step explanation:

Σ ( 9n - 6 ) , n = 1

An = general term.

let Σ (An) = Σ (9n-6)

An = 9n-6

to determine the terms, plug in the value of n into the general term(An)

If you're asked for the 1st term then n = 1

if you're asked for the 2nd term then n = 2. and so forth.

To find the 1st 4 terms, just plug in 1 up to 4 into n bit by bit.

An = 9n - 6

A1 = 9 × 1 - 6 = 3

A2 = 18 - 6 = 12

A3 = 27 - 6 = 21

A4 = 36 - 6 = 30. done.

write the terms from 1 to 4 like this :

{ A1, A2, A3, A4 } = { 3, 12, 21, 30 }.

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Evaluate 8(7x--3) when x=9
Schach [20]

I will assume that by "Evaluate 8(7x--3) when x=9" you meant:

"Evaluate 8(7x-3) when x=9."

First, substitute 9 for x in 7x-3: 7(9)-3 = 60. Rewrite the problem as:

8(60). Multiply. Answer: 480

5 0
3 years ago
Which equation represents the data in the table?
gavmur [86]

Answer:

c

Step-by-step explanation:

It all adds up. Ex; 2*2=4   4-3=1

and continues through the rest of the table

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3 years ago
Which number line correctly shows -3-1.5?​
Papessa [141]
Pretty sure it’s the 3rd
7 0
3 years ago
Read 2 more answers
The sum of the measures of the angles of a triangle is 180. The sum of the measures of the second and third angles is five times
almond37 [142]

Answer:

First angle = 30°

Second angle = 60°

Third angle = 90°

Step-by-step explanation:

x + y + z = 180

y + z = 5x

z = y + 30

then:

y + (y+30) = 5x

2y + 30 = 5x

x = (2y+30)/5

then:

x + y + z = 180

{(2y+30)/5} + y + y+30 = 180

{(2y+30)/5} + 2y + 30 = 180

{(2y+30)/5} = 180 - 30 - 2y

{(2y+30)/5} = 150 - 2y

2y+30 = 5(150-2y)

2y+30 = 5*150 + 5*-2y

2y+30 = 750 - 10y

2y + 10y = 750 - 30

12y = 720

y = 720/12

y = 60°

x = (2y+30)/5

x = (2*60 + 30)/5

x = (120+30)/5

x = 150/5

x = 30°

z = y + 30

z = 60 + 30

z = 90°

Check:

x + y + z = 180°

30° + 60° + 90° = 180°

7 0
3 years ago
Question 13
ArbitrLikvidat [17]

Answer:

C

Step-by-step explanation:

Here in this question , we are interested in calculating the total distance covered by the train in the 10 minutes that it ran.

From the first part of the question, we already know the distances in the first 5 minutes.

Now, to calculate the total distance in the second 5 minutes, we use the distance formula since we have the average speed and the time;

Mathematically; Total distance = average speed * time

From the question, average speed is 33km/h, while time is 5 minutes. To achieve a consistent unit, we convert 5 minutes to hours.

That would be 5/60 = 1/12 hours

So the total distance in the second 5 minutes is;

33 * 1/12 = 2.75 km

Now, to calculate the total distance traveled, let’s add up the distances in the first 5 minutes and convert to kilometers;

That would be;

68 + 127 + 208 + 312 + 535 = 1,250 m

Let’s convert this to km.

We simply divide by 1000 = 1250/1000 = 1.25 km

The total distance is thus ;

1.25 + 2.75 = 4 km

4 0
3 years ago
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