Answer:
A. ERP promises slow, but accurate information.
Explanation:
Option A. ERP promises slow, but accurate, information is incorrect. One of the most important aspects of Enterprise Resource Planning (ERP) has to do with time optimization through its "Automation" features which aim at cutting down several hours of staff work in performing tedious tasks. Accuracy in information is a must.
Among other important features and capabilities of ERP, it is worth mentioning:
1. Integration
2. Automation
3. Reporting
4. Tracking and Visibility
5. Data Analysis
6. Accounting
7. Customer Relationship Management
Answer:
You can use the following websites for more of a simple and smooth experience
SoGoSurvey.
Survey Monkey.
Typeform.
Google Forms.
Client Heartbeat.
Zoho Survey.
Survey Gizmo.
Survey Planet.
Hope this helped!
Explanation:
Answer:
Following are the program in python language
def prob3_6(k): #function definition
c = 0 #variable declaration
while k != 1: #iterating the while loop
print(k) #print k
if k % 2 == 0:#check if condition
k= k // 2 #divisible by 2
else: #else condition
k = k * 3 + 1
c = c + 1
print(k) #print k
print c #print count
prob3_6(3)#function call
Output:
3
10
5
16
8
4
2
1
7
Explanation:
Following are the description of program
- Create a function "prob3_6" in this function we passing an integer parameter of type "int" named "k".
- Inside that function we declared a variable "c" of type "int" that is used for counting purpose .
- After that we iterated the while for print the value of when it is not equal to 1 .
- We check if condition when k gives 0 on modulus then k is divisible by 2 otherwise else block will be executed in the else part we multiply by 3 to k and add 1 to the k variable .
- Finally print "k" and "c"
Answer:
import java.util.Scanner;
public class Main
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter a number: ");
int userVal = input.nextInt();
String aString;
if(userVal < 0)
aString = "negative";
else
aString = "non-negative";
System.out.println(aString);
}
}
Explanation:
Ask the user to enter a number and set it to userVal
Check the value of userVal. If it is smaller than 0, set the string as "negative". If it is not, set it as "non-negative"
Print the string
import java.util.Scanner;
public class U2_L3_Activity_Four {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter a sentence.");
String sent = scan.nextLine();
int count = 0;
for (int i = 0; i < sent.length(); i++){
char c = sent.charAt(i);
if (c != ' '){
count++;
}
else{
break;
}
}
System.out.println("The first word is " + count +" letters long");
}
}
We check to see when the first space occurs in our string and we add one to our count variable for every letter before that. I hope this helps!
