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Reptile [31]
3 years ago
14

You have just starting working at Quantum Company. As a new programmer, you have been asked to review and correct various pseudo

code. The following pseudocode checks if an item number is valid: start Declarations num sub = 0 num SIZE = 5 num VALID_ITEM [5] = 27,53,84,89,95 string foundIt = "N" input item while sub < SIZE if item = VALID_ITEM[sub] then foundIt = "Y" endif sub = sub +1 endwhile if foundIt = "Y" then output "Valid item number" else output "Invalid item number" endif stop Which while loop makes this more efficient?
Computers and Technology
1 answer:
Alecsey [184]3 years ago
8 0

Answer:

The correct answer to the following question:

while sub < SIZE AND foundIt = "N"

Explanation:

Firstly, we start the pseudocode after that set the variable sub to 0 and size to 1 of num type and also set a num type array VALID_ITEM[5] and its elements are 27,53,84,89,95.

Than set string type variable foundIt to "N", then we set a while loop and correct its condition is "< SIZE AND foundIt = "N" ".

Than starts if condition which is "item = VALID_ITEM[sub]", if the condition is true than foundIt = "Y", after that endif.

Than increment the variable sub, after that endwhile, after this, we start if condition which is "foundIt = "Y" " if the condition is true then output "Valid item number" or else "Invalid item number", and then we endif and after all stop the pseudocode.

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frutty [35]

Answer:

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c=1.5708

Explanation:

Use this script in Matlab:

-------------------------------------------------------------------------------------

function  [c, err, yc] = bisect (f, a, b, delta)

% f the function introduce as n anonymous function

%       - a y b are the initial and the final value respectively

%       - delta is the tolerance or error.

%           - c is the root

%       - yc = f(c)

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ya = feval(f, a);

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max1 = 1 + round((log(b-a) - log(delta)) / log(2));

for  k = 1:max1

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yc = feval(f, c);

if  yc == 0

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c = (a + b) / 2;

err = abs(b - a);

yc = feval(f, c);

-------------------------------------------------------------------------------------

Enter the function in matlab like this:

f= @(x) 0.005*(exp(2*x)*cos(x))

You should get this result:

f =

 function_handle with value:

   @(x)0.005*(exp(2*x)*cos(x))

Now run the code like this:

[c, err, yc] = bisect (f, 1, 2, 1e-10)

You should get this result:

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err =

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yc =

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In addition, you can use the plot function to verify your results:

fplot(f,[1,2])

grid on

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