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zhenek [66]
3 years ago
5

What is -63 divided by 7

Mathematics
2 answers:
FinnZ [79.3K]3 years ago
8 0

Answer:

-9

Step-by-step explanation: a negative multiplied or divided by a positive will give you a negative answer

Fiesta28 [93]3 years ago
4 0

Answer: -9


Step-by-step explanation:

Divide -63 and 7. Seven goes in 9 time in -63. Then you take the sign that has the bigger number then you will get your answer

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A circle with circumference 6 has an arc with a 60° central angle.
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Answer:

  1

Step-by-step explanation:

60° is 1/6 of the total number of degrees that make up a circle. Then 1/6 of the total circumference that makes up the circle is ...

  (1/6)(6 units) = 1 unit

The arc length is 1 unit.

5 0
3 years ago
According to this diagram, what is tan 67° ?
Zanzabum

Answer:

B. 12/5

Step-by-step explanation:

tan=opp. leg/adj. leg

tan 67= 12/5

6 0
3 years ago
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Pls help me!! thank you!!
klasskru [66]

Full working out shown from step 1 to last.

follow it and you get 24 square feet as final answer. Good luck in other questions!!!

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3 years ago
Find the area of the region which is inside the polar curve r=5sin(θ) but outside r=4. Round your answer to four decimal places
natka813 [3]

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be 3.75 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be

Then the intersection point will be given as

\rm 5 \sin \theta  = 4\\\\\theta = 0.927 , 2.214

Then by the integration, we have

\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214}[ (5 \sin \theta)^2 - 4^2] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [25\sin ^2 \theta - 16] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [ \dfrac{25}{2}(1 - \cos 2\theta ) - 16] d\theta \\

\rightarrow \dfrac{1}{2} [\dfrac{25 \theta }{5} - \dfrac{25 \cos 2\theta }{2} - 16\theta]_{0.927}^{2.214} \\\\\\\rightarrow \dfrac{1}{2} [\dfrac{25(2.214 - 0.927) }{5} - \dfrac{25 (\cos 2\times 2.214 - \cos 2\times 0.927) }{2} - 16(2.214 - 0.927]\\

On solving, we have

\rightarrow \dfrac{1}{2} \times 7.499\\\\\rightarrow 3.75

Thus, the area of the region is 3.75 square units.

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

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2 years ago
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