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san4es73 [151]
3 years ago
9

If Company M ordered a total of 50 computers and printers and Company N ordered a total of 60 computers and printers, how many c

omputers did Company M order?
(1) Company M and Company N ordered the same number of computers.
(2) Company N ordered 10 more printers than Company M.
Mathematics
1 answer:
Ad libitum [116K]3 years ago
6 0

Answer:

Available information is not sufficient to solve the questions

Step-by-step explanation:

Let Cm = Computers Ordered by Company M

Let Cn = Computers Ordered by Company N

Let Pm = Printers Ordered by Company M

Let Pn = Printers Ordered by Company N

Cm + Pm = 50 --- Equation 1

Cn + Pn = 60 ----- Equation 2

1. Company M and N ordered the same number of computers

Here,

Cm = Cn

Substitute Cm for Cn in equation 2

Cm + Pm = 50

Cm + Pn = 60

Subtract Equation 2 from 1

Pm - Pn = 50 - 60

Pm - Pn = -10

Pm = Pn - 10

Substitute Pn-10 for Pm in equation 1

Cm + Pn - 10 = 50

Make Pn the subject of formula

Cm = 50+10-Pn

Cm = 60 - Pn

Hence, the number of computers ordered by Company M is 60 minus the number of printers ordered by Company n

2. Company N ordered 10 more printers than Company M.

Here,

Pn = 10 + Pm

Make Pm the subject of formula

Pm = Pn - 10

Substitute Pn-10 for Pm in equation 1

Cm + Pn - 10 = 50

Make Cm the Subject of formula

Cm = 50 + 10 - Pn

Cm = 60 - Pn

Hence, the number of computers ordered by Company M is 60 minus the number of printers ordered by Company n

Condition 1 and 2 points to the same result

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