The answer is c.. Just use the distributive property on c and it will equal what you have to factor
Answer:
Step-by-step explanation:
We can get this done by using the code
def digits(n):
count = 0
if n == 0:
return 1
while (n > 0):
count += 1
n= n//10
return count
Also, another way of putting it is by saying
def digits(n):
return len(str(n))
------------------------------------------
print(digits(25)) # Should print 2
print(digits(144)) # Should print 3
print(digits(1000)) # Should print 4
print(digits(0)) # Should print 1
Doing this way, we've told the system to count the number of figures that exist in the number. If it's 1000 to 9999, then it records it as 4 digits. If it's 100 - 999, then it records it as 3 digits. If it's 10 - 99, it records as 2 digits. If it's 0 - 9, then it has to record it as a single digit.
Thanks
I would start like this: which year was the seventh AMC 8??
the first was in 1985
The second: 1986
3: 1987
4: 1988
5: 1989
6: 1990
7: 1991
so seventh AMC 8 took place in 1991.
she was then 12, so we can subtract this age from 1991:
1991-12=1979
so she was born in 1979!
Find common denominators and move from there
