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Ymorist [56]
3 years ago
13

PLZ HELP

Mathematics
2 answers:
Setler [38]3 years ago
6 0
£1.00= 100 cents, 100- 64 = 36.

36
Marysya12 [62]3 years ago
6 0
If you convert the dollars into cents you get 100 cent where you could subtract 100-64=46
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8

Step-by-step explanation:

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Please help me i do not understand explain how you answer the following questions.
dlinn [17]

For 6, you could divide 56 kilometers by 8 kilometers to get 7 kilometers. Multiply 7 by 5 to get 35. There would be 35 miles in 56 kilometers

7 0
2 years ago
36 3⁄4 gallons of water come out of a hose in 15 minutes. Write the ratio in fractional form and determine the water rate in gal
Brrunno [24]

Answer:

Step-by-step explanation:

If 3⁄4 gallons of water come out of a hose in 15 minutes, to calculate the rate of water that comes out in an hour (60 minutes), we will use the expression;

3/4 gallons = 15 minutes

x gallons = 60minutes

cross multiply

15x = 3/4 * 60

15x = 180/4

15x = 45

x = 45/15

x = 3/1

x = 3:1

Hence the water rate in gallons per hour is 3 gallons per hour

7 0
3 years ago
To find proportion of the area under the normal curve between two Z scores that are both above the mean, it is necessary to exam
VikaD [51]

It is necessary to imagine the sum of the areas between each z-score and the average.

Given as the ratio of the area under the normal curve between two z-scores, both above average.

The  Z score accurately measures the number of standard deviations above or below the mean of the data points.

The formula for calculating the z-score is

z = (data points – mean) / (standard deviation).

It is also expressed as z = (x-μ) / σ.

  • A positive z-score indicates that the data points are above average.
  • A negative z-score indicates that the data points are below average.
  • A z-score close to 0 means that the data points are close to average.
  • The normal curve is symmetric with respect to the mean and needs to be investigated.

Therefore, to find the percentage of the area under the normal curve between two z-scores, both above the mean, you need to look at the sum of the areas between the z-score and the mean.

Learn more about z-score from here brainly.com/question/16768891

#SPJ4

7 0
1 year ago
A national survey of companies included a question that asked whether the company had at least one bilingual telephone operator.
nirvana33 [79]

Answer:

The first option is correct. Option A is correct.

LCL = 0.270, and UCL = 0.397

80% Confidence interval = (0.270, 0.397)

Step-by-step explanation:

The data for Y and N for the 90 companies is attached to this solution provided.

Y represents companies with at least 1 bilingual operator and N represents companies with no bilingual operator.

The number of Y in the data = 30

Hence, sample proportion of companies with at least one bilingual operator = (30/90) = 0.3333

Confidence Interval for the population proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample proportion) ± (Margin of error)

Sample proportion = 0.3333

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error)

Critical value at 80% confidence level for sample size of 90 is obtained from the z-tables.

Critical value = 1.280

Standard error of the mean = σₓ = √[p(1-p)/n]

p = sample proportion

n = sample size = 90

σₓ = √[0.3333×0.6667)/90] = 0.0496891568 = 0.04969

80% Confidence Interval = (Sample proportion) ± [(Critical value) × (standard Error)]

CI = 0.3333 ± (1.28 × 0.04969)

CI = 0.3333 ± 0.0636021207

80% CI = (0.2696978793, 0.3969021207)

80% Confidence interval = (0.270, 0.397)

Hope this Helps!!!

3 0
3 years ago
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