The drama teacher decreased the length of a play from 90 minutes to 60 minutes. What was the percent decrease in the length of t
1 answer:
You might be interested in
Answer:
Option (2). Increasing x > 0; decreasing x < 0
Step-by-step explanation:
Equation of the parabola having vertex (0, 3) will be,
y = (x - 0)² + 3
y = x² + 3
To check the function is increasing or decreasing in the given intervals we will find the derivative of the function,
y' = 2x
For x < 0 Or x = -1
y' = 2(-1)
= -2 < 0
Therefore, function is decreasing in x < 0
For x > 0 Or x = 1
y' = 2(1) + 3
= 5 > 0
Therefore, function is increasing in x > 0
Option (2) is the answer.
<u>Step-by-step explanation:</u>
transform the parent graph of f(x) = ln x into f(x) = - ln (x - 4) by shifting the parent graph 4 units to the right and reflecting over the x-axis
(???, 0): 0 = - ln (x - 4)
0 = ln (x - 4)
1 = x - 4
<u> +4 </u> <u> +4 </u>
5 = x
(5, 0)
(???, 1): 1 = - ln (x - 4)
1 = ln (x - 4)
e = x - 4
<u> +4 </u> <u> +4 </u>
e + 4 = x
6.72 = x
(6.72, 1)
Domain: x - 4 > 0
<u> +4 </u> <u>+4 </u>
x > 4
(4, ∞)
Vertical asymptotes: there are no vertical asymptotes for the parent function and the transformation did not alter that
No vertical asymptotes
*************************************************************************
transform the parent graph of f(x) = 3ˣ into f(x) = - 3ˣ⁺⁵ by shifting the parent graph 5 units to the left and reflecting over the x-axis
Domain: there is no restriction on x so domain is all real number
(-∞, ∞)
Range: there is a horizontal asymptote for the parent graph of y = 0 with range of y > 0. the transformation is a reflection over the x-axis so the horizontal asymptote is the same (y = 0) but the range changed to y < 0.
(-∞, 0)
Y-intercept is when x = 0:
f(x) = - 3ˣ⁺⁵
= - 3⁰⁺⁵
= - 3⁵
= -243
Horizontal Asymptote: y = 0 <em>(explanation above)</em>
