After you type in your equations and hit graph you notice that, if you are in the standard window, your parabola is cut off so you have to choose your "window" button to change the viewing window to see the whole graph. Then you would use your 2nd button and "trace" and "intersect" to find the points of intersection of the 2 graphs. The first point is at (-.90901, 16.81812) and the second point is at (5.9090909, 3.1818182). Graphing calculators are quite amazing!
If Point C and D are equidistant from point A, it means that AC and AD are of the same length. AC = AD
AC = AD (S) (<span>Points C and D are equidistant from point A)
</span>AE = AE (S) (The two triangle shared the same side)
∠CAE = ∠EAD (A) (This angle is between the two sides that we just proved to be equal)
By SAS,
ΔEAD ≡ ΔEAC
The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
<h3>How to identify similar triangles?</h3>
From the image attached, we see that we are given the Parallelogram GRPC. Thus;
A. The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;
∠CGB ≅ ∠PEB (Alternate Interior Angles)
∠BPE ≅ ∠BCG (Alternate Interior Angles)
∠GBC ≅ ∠EBP (Vertical Angles)
C. To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;
225/325 = PE/375
PE = 260 ft
BE/425 = 225/325
BE = 294 ft
Read more about Similar Triangles at; brainly.com/question/14285697
#SPJ1
It will be 3 weeks because if you divide 7/2,100 it will become to be 3weeks
For option a, y = 3(4) - 1 = 12 - 1 = 11 [not correct]
For option b, y = 3(2) - 1 = 6 - 1 = 5 [correct]
Therefore option b is a solution to the given equation.
