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VARVARA [1.3K]
3 years ago
10

Pls help with the matching

Mathematics
2 answers:
Ronch [10]3 years ago
6 0
12-y=9
3x-y=21
4y-10=2
1/4xy=6
Stells [14]3 years ago
4 0

Answer:

12-y= 9

3x-y=21

4y-10=2

1/4xy=6

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A confectioner bought 15 chocolates for Rs. 1. If he sold all chocolates at 25% profit, how many chocolates were sold for Rs. 1?
shutvik [7]

Answer:

He sold 12 chocolates for 1 Re.

Step-by-step explanation:

He bought 15 chocolates for 1 Rupee

He sold for a profit of 25%

Sale price = profit + cost price

SP= 25%of 1 + 1 Re

SP = 0.25*1+ 1

SP = 1.25 Rs

He sold 15 chocolates fro 1.25 Rs

Chocolates            Rupees

15                            1.25

x                                1

Applying cross product

x*1.25= 15*1

x= 15*1/1.25

x= 12

He sold 12 chocolates for 1 Re.

4 0
2 years ago
How would I solve this?? 5p-8(p+1)>16
alexandr402 [8]

<em>*To solve inequalities is similar to solving equations: isolate the desired variable to one side.</em>

So firstly, distribute -8 to (p + 1):

5p-8p-8>16

Next, combine like terms:

-3p-8>16

Next, add 8 to both sides:

-3p>24

Lastly, divide both sides by -3. Now since you are dividing by a <u>negative</u>, you will be flipping the inequality symbol as well.<u> Your final answer will be p</u>

6 0
3 years ago
Help please thanks!
g100num [7]

I got 1:4

What I did was added all the catfish samples which was 15. Then I added all the samples together and got 60. I then put them in the ratio and simplified them.

15:60

1:4

4 0
2 years ago
Read 2 more answers
What is the velocity of a car that traveled a total of 75 km north in 1.5 hours
Korvikt [17]

Answer:

13.89 m/s

Step-by-step explanation:

Velocity = displacement = time

75 km = 75000 m

1.5 hours = 5400 sec

applying the formula

velocity = 75000 m= 5400 s = 13.89 m/s

7 0
2 years ago
Read 2 more answers
0=4t-16t^2 Solve this please
vaieri [72.5K]

Answer:

\large\boxed{t=0\ \vee\ t=\dfrac{1}{4}}

Step-by-step explanation:

4t-16t^2=0\qquad\text{divide both sides by 4}\\\\\dfrac{4t}{4}-\dfrac{16t^2}{4}=\dfrac{0}{4}\\\\t-4t^2=0\\\\t(1-4t)=0\iff t=0\ \vee\ 1-4t=0\\\\1-4t=0\qquad\text{subtract 1 from both sides}\\\\-4t=-1\qquad\text{divide both sides by (-4)}\\\\t=\dfrac{1}{4}

7 0
3 years ago
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