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2 years ago

Pls help with the matching

Mathematics

2 answers:

Ronch [10]2 years ago

6 0

12-y=9
3x-y=21
4y-10=2
1/4xy=6

Stells [14]2 years ago

4 0

Answer:

12-y= 9

3x-y=21

4y-10=2

1/4xy=6

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Please Please help!

Mice21 [21]

Answer:

Step-by-step explanation:

x²+3x+2=0

x²+x+2x+2=0

x(x+1)+2(x+1)=0

(x+1)(x+2)=0

x=-1,x=-2

so B

6 0

2 years ago

Beatrice charges $10/h and gets a $5 automatic tip. Beatrice needs $100 to buy a present for her mother. She wants to find out t

Evgesh-ka [11]

10+5=15 so $100/15= 6.67hrs. She could work about 7hrs.
she could work 7 hrs if rounded to nearest tenth

8 0

3 years ago

Twenty percent of drivers driving between 10 pm and 3 am are drunken drivers. In a random sample of 12 drivers driving between 1

Lesechka [4]

Answer:

(a) 0.28347

(b) 0.36909

(d) 0.9806

Step-by-step explanation:

Given information:

n=12

p = 20% = 0.2

q = 1-p = 1-0.2 = 0.8

Binomial formula:

$P(x=r)=^nC_rp^rq^{n-r}$

(a) Exactly two will be drunken drivers.

$P(x=2)=^{12}C_{2}(0.2)^{2}(0.8)^{12-2}$

$P(x=2)=66(0.2)^{2}(0.8)^{10}$

$P(x=2)=\approx 0.28347$

Therefore, the probability that exactly two will be drunken drivers is 0.28347.

(b)Three or four will be drunken drivers.

$P(x=3\text{ or }x=4)=P(x=3)\cup P(x=4)$

$P(x=3\text{ or }x=4)=P(x=3)+P(x=4)$

Using binomial we get

$P(x=3\text{ or }x=4)=^{12}C_{3}(0.2)^{3}(0.8)^{12-3}+^{12}C_{4}(0.2)^{4}(0.8)^{12-4}$

$P(x=3\text{ or }x=4)=0.236223+0.132876$

$P(x=3\text{ or }x=4)\approx 0.369099$

Therefore, the probability that three or four will be drunken drivers is 0.3691.

(c)

At least 7 will be drunken drivers.

$P(x\geq 7)=1-P(x$

$P(x\leq 7)=1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)+P(x=6)]$

$P(x\leq 7)=1-[0.06872+0.20616+0.28347+0.23622+0.13288+0.05315+0.0155]$

$P(x\leq 7)=1-[0.9961]$

$P(x\leq 7)=0.0039$

Therefore, the probability of at least 7 will be drunken drivers is 0.0039.

(d) At most 5 will be drunken drivers.

$P(x\leq 5)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)$

$P(x\leq 5)=0.06872+0.20616+0.28347+0.23622+0.13288+0.05315$

$P(x\leq 5)=0.9806$

Therefore, the probability of at most 5 will be drunken drivers is 0.9806.

5 0

3 years ago

A retailer sells a refrigerator for a list price of $1,200. The retailers cost was $850. What is the percentage of the markup?

matrenka [14]

Answer:

41%

Step-by-step explanation:

1200-850=350

350 is the markup, now we need the percentage

the orginal price was 850 so we just need to divide 350 by 850

we get 0.4117...

convert that to a percentage and we have 41% markup

8 0

2 years ago

Please help me please I don’t understand and my teacher said I got it wrong for numbers 1 2 and 3

kirza4 [7]

Answer:

1) 5/9

2) 4/7

3) 3/8

Step-by-step explanation:

1) 5/9

2) 4/7

3)3/8

3 0

2 years ago

Read 2 more answers