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Anettt [7]
3 years ago
15

The inverse of a cubic function is also a function.

Mathematics
2 answers:
Eduardwww [97]3 years ago
7 0
<h3>Answer:</h3>

b. sometimes true

<h3>Explanation:</h3>

If the derivative of the cubic has two real zeros, the inverse relation will not pass the verical line test.

_____

The attached graph shows two inverse cubic relations, one a function, one not.

Tju [1.3M]3 years ago
4 0

Answer:

1. B. Sometimes True

2. A. Always True

Hope I helped! :)

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Pleaseee answer asap worth 17 pts
bija089 [108]
Speed=distance/time
average speed=(total distance)/(total time)

total distance=203+243=446
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average speed=(446)/(8)=55.75


answer is A
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3 years ago
The product of 4 and a number is 5.6.<br><br> What is the number?
hodyreva [135]
Let this number be represented by the variable "n"

product of 4 and n is multiplying4 and n

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Write <br> 39<br> 100<br> as a decimal number
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39.0 is the decimal for it
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3 years ago
Read 2 more answers
Which is longer 2 meters or 200 cent a meters or 2.05 meters
Yuri [45]
Solving this requires use of conversions

we already know that
2.05 m > 2 m

all that's left is the question
200 cm vs. 2.05 meters

I we know our equivalencies, we know that
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6 0
3 years ago
Cubed root x cubed root x2​
Yuki888 [10]

Answer:

Final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

Step-by-step explanation:

Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

Now we need to simplify this problem.

\sqrt[3]{x}\cdot\sqrt[3]{x^2}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}

Apply formula

\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}

so we get:

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x

Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

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3 years ago
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