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anastassius [24]
3 years ago
9

One month dale rented 6 movies and 2 video games for a total of $36. The next month he rented 3 movies and 5 videos games for a

total of $39
Mathematics
2 answers:
Anna [14]3 years ago
5 0

Answewhat are you spost to figur out?


Step-by-step explanation:


Verdich [7]3 years ago
5 0

Answer:

movie = $4.25

vg = $5.25

Step-by-step explanation:

let x = $ of a movie

let y = $ of a vg

6x + 2y = 36

3x + 5y = 39

multiply the first one by 3 and the second by 6

18x + 6y = 108

18x + 30y = 234

subtract

18x cancels out 18x

-24y = -126

divide -126 by -24

y= $5.25

plug y into first equation

x= $4.25

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√44 is between what 2 numbers?<br><br> A.4 and 5<br> B.5 and 6<br> C.6 and 7<br> D.7 and 8
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I believe the answer is C.

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4 years ago
If the equations 2x +y =7 and x-y=2are solved simultaneously, then y=_________​
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Answer:

y = -2x + 7 and y = x - 2

Step-by-step explanation:

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7 0
2 years ago
The sales of a grocery store had an average of $8,000 per day. The store introduced several advertising campaigns in order to in
oksano4ka [1.4K]

Answer:

Null hypothesis:\mu \leq 8000  

Alternative hypothesis:\mu > 8000  

z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2  

p_v =P(Z>2)=0.0228  

Step-by-step explanation:

1) Data given and notation  

\bar X=8300 represent the sample mean  

\sigma=1200 represent the population standard deviation  

n=64 sample size  

\mu_o =800 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 8000, the system of hypothesis are :  

Null hypothesis:\mu \leq 8000  

Alternative hypothesis:\mu > 8000  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2  

4) P-value  

Since is a one-side upper test the p value would given by:  

p_v =P(Z>2)=0.0228  

5) Conclusion  

If we compare the p value and the significance level assumed, for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than $8000.  

4 0
3 years ago
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