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andreev551 [17]
3 years ago
8

Show how you solve the following two equations: 6x = 33 2/3x=8/15

Mathematics
2 answers:
LuckyWell [14K]3 years ago
4 0
6x = 33 x= 33/6. x= 5 3/6 = 5 1/3


2/3x=8/15= x= 8/15÷2/3 x= 8/15 x 3/2 = 24/30 = 4/5
astra-53 [7]3 years ago
3 0
Here you go, I hope this helps! :)

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7.5 x 18.74 show your work
FinnZ [79.3K]
7.5x18.74= 140.55 is the correct answer
7 0
2 years ago
Please help will mark brainliest if correct
sesenic [268]

Answer:

Step-by-step explanation:

<u><em>The triangles can not be proven congruent.</em></u>

We have AAA theorem ⇒ given triangles are similar for sure.

3 0
3 years ago
Robert is a high school basketball player. In a particular game, he made some three point shots and some free throws (worth one
Oksanka [162]

Answer:

let t = number of three-point shots

let f = number of free throw shots

Step-by-step explanation:

t + f = 9      (he made a total of 9 shots altogether)

3t + 1f = 23   (number of shots multiplied by their point value)

substitution method:   t = 9 - f

                                    3(9 - f) + f = 23

                                     27 - 3f + f = 23

                                      -2f = -4

                                         f = 2

find 't':                               t + 2 = 9

                                         t = 7

                                         

8 0
3 years ago
Jack looks at a clock tower from a distance and determines that the angle of elevation of the top of the tower is 40°. John, who
zmey [24]

Answer:

18.7939 m

Step-by-step explanation:

-Let x be the distance between John and clock tower.

-Let y be the vertical distance from the eyes of the two men  standing to the top of the clock tower.

#Taking the right triangle ACD:

\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 60\textdegree=\frac{y+1.5}{x}\\\\y=x \ Tan \ 60\textdegree -1.5

#Taking the right triangle ABD:

\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 40\textdegree=\frac{y+1.5}{x+20}\\\\y=(x+20)\ Tan \ 40\textdegree -1.5

#We equate the two yo solve for x and y;

(x+20)\ Tan \ 40\textdegree -1.5=x\ Tan \ 60\textdegree -1.5\\\\(x+20)\ Tan \ 40\textdegree=x\ Tan \ 60\textdegree\\\\0.8391x+16.7820=1.7321x\\\\x=18.7939

Hence, John's distance from the tower's base is 18.7939 m

8 0
2 years ago
Plz help I will give anyone who answers this correctly 100 points.
dsp73

Answer:

126.

Step-by-step explanation:

Each rectangle is a step. We'll start with the top one. This is simple: 6 times 3.

6 * 3 = 18.

The farthest left is 5 times 3.

5 * 3 = 15.

The crossed one is 6 times 5.

6 * 5 = 30.

The one to the right of the crossed one is 3 times 5, again.

3 * 5 = 15.

The farthest right is 6 times 5, again.

6 * 5 = 30.

The bottom one is 6 times 3, again.

6 * 3 = 18.

Now, we add.

18 + 18 = 36.\\15 + 15 = 30.\\30 + 30 = 60.\\36 + 30 + 60 = 126.

8 0
3 years ago
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