1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stiks02 [169]
3 years ago
8

OH NO!!! Madeleine’s data has been corrupted, again! Using the incomplete data file below, which she was able to recover from he

r hard drive, can you help finish her analysis? She needs to calculate:
(note: you DO NOT need to fill in all the missing data. You only need to calculate the statistics listed below)

A) N

B) The mean of set X

C) The mean of set Y

D) SSx

E) Σ(X) × Σ(Y)

F) SSxy

G) √ ( SSx × SSy)

H) r

I ) b (slope)

J ) a (intercept)

Mathematics
1 answer:
-Dominant- [34]3 years ago
3 0

Answer:

a. N=25

b. X[bar]= 60.52

c. Y[bar]= 106.72

d. SSx= 115.24

e. ∑X*∑Y = 4036684

f. SSxy= 202020.3296

g. √(SSx*SSy)= 449.46

Step-by-step explanation:

Hello!

Using the attached data you need to calculate some statistics.

a) N

The sample size is listed under the first column "subject" You can see that 25 subjects qhere studied so N=25.

b.

The mean of set X is equal to X[bar]= ∑X/n= 1513/25= 60.52

∑X is listed in the second table.

c.

The mean of ser Y is Y[bar]= ∑Y/n= 2668/25= 106.72

∑Y is listed in the second table.

d.

Sum of Squares of set X SSx= ∑X²-[(∑X)²/n]= 91682-[(1513)²/25]= 115.24

e.

∑X*∑Y =1513*2668= 4036684

f.

SSxy= (∑X²-[(∑X)²/n]) * (∑Y²-[(∑Y)²/n])= (91682-[(1513)²/25]) * (286482*[(2668)²/25])= 202020.3296

g.

√(SSx*SSy)= √(115.24*1753)= 449.46

I hope you have a SUPER day!

You might be interested in
True or False
BigorU [14]

Answer:

1. false

2. true

3. true

4. true

5. true

6. false

Step-by-step explanation:

sub to tapl :L

3 0
2 years ago
Victoria jogged 3/4 Mile in 1/5 of an hour. At this pace,how far will she jog in an hour
OLga [1]
I think is 3/20.....
5 0
3 years ago
Read 2 more answers
What is a recriprocal of 25
Arturiano [62]

Answer:

1/25

The fraction for 25 would be 25/1 so the recripocal of 25/1 would be 1/25. The reciprocal is the numerator and denominator switched.

8 0
3 years ago
Read 2 more answers
Which of the following man did not help write the federalism papers
IrinaVladis [17]

I believe the correct answer is D Aarron Burr

4 0
3 years ago
Drag and drop the constant of proportionality into the box to match the table. If the table is not proportional, drag and drop "
Travka [436]

Answer:  3/2

Step-by-step explanation:

Since, two variables are called proportional if there is always a constant ratio between them.

And, The constant is called the coefficient of proportionality or proportionality constant.

Let x and y are  proportional to each other.

Therefore, x ∝ y ⇒ y=kx

Where k is any constant.

For, x=2 and y=3 k= 3/2

For, x=4 and y=6, k=3/2

For x=6 and y=9, k= 3/2

Since, here the value of k is constant.

Therefore, k is the coefficient of proportionality.

And, given table is propositional.


3 0
4 years ago
Other questions:
  • Please help me I stink at math need all
    15·1 answer
  • Solve -1/2w -3/5=1/5w
    15·1 answer
  • A rectagle has a height of 5x and a width of x+2<br><br>area=???​
    15·1 answer
  • HELP MEH Which is one factor that affects the type of cloud that will form?
    6·2 answers
  • 8.21 as a mkxed number
    8·2 answers
  • Pleaseeee help me with 1-13 IM DESPERATE
    12·1 answer
  • In this 45-46-90 triangle , I have been given the length of a leg . How do I find the length of the hypotenuse
    5·2 answers
  • John want to buy a pair of boots that originally cost $85.99 He found a coupon for %30 off what will he pay for the boots?
    7·2 answers
  • A farmer sells 8.6 kg of apples and pears at the farmers market 2/5 of the weight is apples and the rest is pears how many kilog
    13·1 answer
  • Simplify using the laws of exponents: (x4)6 = x2 x10 x24 x48
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!