Answer:
a. N=25
b. X[bar]= 60.52
c. Y[bar]= 106.72
d. SSx= 115.24
e. ∑X*∑Y = 4036684
f. SSxy= 202020.3296
g. √(SSx*SSy)= 449.46
Step-by-step explanation:
Hello!
Using the attached data you need to calculate some statistics.
a) N
The sample size is listed under the first column "subject" You can see that 25 subjects qhere studied so N=25.
b.
The mean of set X is equal to X[bar]= ∑X/n= 1513/25= 60.52
∑X is listed in the second table.
c.
The mean of ser Y is Y[bar]= ∑Y/n= 2668/25= 106.72
∑Y is listed in the second table.
d.
Sum of Squares of set X SSx= ∑X²-[(∑X)²/n]= 91682-[(1513)²/25]= 115.24
e.
∑X*∑Y =1513*2668= 4036684
f.
SSxy= (∑X²-[(∑X)²/n]) * (∑Y²-[(∑Y)²/n])= (91682-[(1513)²/25]) * (286482*[(2668)²/25])= 202020.3296
g.
√(SSx*SSy)= √(115.24*1753)= 449.46
I hope you have a SUPER day!
Answer: £ 400,560,640
Step-by-step explanation:
Given
Delia, Edwin, and Freya share £1600 in the ratio
Suppose, their shares are 5x,7x, and 8x such that the ratio remains the same.
The sum of their shares must be £1600
Their share is
Delia:
Edwin:
Freya:
Answer:
The true statements are
1. BD = DB'
3. m∠EFA = 90°
4. The line of reflection, EH, is the perpendicular bisector of BB', AA', and
CC'
Step-by-step explanation:
* Lets explain how to solve the problem
- Reflection is flipping an object over the line of reflection.
- The object and its image have the same shape and size, but the
figures are in opposite directions from the line of reflection
- The objects appear as if they are mirror reflections, with right and left
reversed
- The line of reflection is a perpendicular bisector for all lines joining
points on the figure with their corresponding images
- Look to the attached figure for more understand
* Lets solve the problem
- ΔA'B'C' was constructed using ΔABC and line segment EH, where
EH is the reflection line
- D is the mid-point of BB'
- F is the mid-point of AA'
- G is the mid-point of CC'
* Lets find from the answer the true statements
1. BD = DB'
∵ D is the mid point of BB'
- Point D divides BB' into two equal parts
∴ BD = DB' ⇒ <em>True</em>
2. DF = FG
- It depends on the size of the sides and angles of the triangle
∵ We can't prove that
∴ DF = FG ⇒ <em>Not true</em>
3. m∠EFA = 90°
∵ The line of reflection ⊥ the lines joining the points with their
corresponding images
∴ EH ⊥ AA' and bisect it at F
∴ m∠EFA = 90° ⇒ <em>True</em>
4. The line of reflection, EH, is the perpendicular bisector of BB',
AA', and CC'
- Yes the line of reflection is perpendicular bisectors of them
∴ The line of reflection, EH, is the perpendicular bisector of BB',
AA', and CC' ⇒ <em>True</em>
5. ΔABC is not congruent to ΔA'B'C'
∵ In reflection the object and its image have the same shape and size
∴ Δ ABC is congruent to Δ A'B'C'
∴ ΔABC is not congruent to ΔA'B'C' ⇒ <em>Not true</em>
