Question

I need help please!!!! Thank you :)

Answer 1

Answer:

The correct options are: Option A, C and D

Step-by-step explanation:

We need to choose correct options by solving the given system of equations.

$3x+4y=18\\2x-2y=2$

Let:

$3x+4y=18--eq(1)\\2x-2y=2--eq(2)$

First Multiply equation 2 by 2 and add both equations.

$3x+4y=18\\4x-4y=4\\------\\7x=22\\x=\frac{22}{7}\\x=3.14$

Now, we will put value of x in equation 2 to find value of y

$2x-2y=2\\2(3.14)-2y=2\\6.28-2y=2\\-2y=2-6.28\\-2y=-4.28\\y=\frac{-4.28}{-2}\\y=2.14$

So, we get x = 3.14 and y = 2.14

Solution set is (3.14,2.14)

The given solution set (2,3) is not the solution of system of equations.

If we put x=2 and y =3 in the first equation:

$3x+4y=18\\3(2)+4(3)=18\\6+12=18\\18=18$

(2,3) when substituted in the First equation the equation is True.

If we put x=2 and y =3 in the second equation:

$2x-2y=2\\2(2)-2(3)=2\\4-6=2\\-2\neq 2$

So, (2,3) when substituted in the second equation the equation is false.

The correct options are: Option A, C and D