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timofeeve [1]
3 years ago
12

let g(x)=x+2. Find f(x) if f(x) is a quadratic function of the form f(x)=ax^2+bx+c and f(g(x))=2x^2-x+3

Mathematics
1 answer:
maw [93]3 years ago
5 0
Let g(x) = x + 2
f(g(x)) = 2x^2 - x + 3
= 2(x^2 - x/2 + 3/2)
=2 (x^2 + 4x + 4) - 9x - 5
=2 (x+2)^2 - 9(x+5/9)
=2 (x + 2)^2 - 9 (x + 2) +13
f(x) = 2x^2 -9x + 13

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Use equivlant ratios 7/= 21/27
sp2606 [1]

Answer:

7/9 = 21/27 hope this helps

Step-by-step explanation:

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identify the graph of 9x^2-25y^2=225 for t(0 5) and write an equation of the translated or rotated graph in general form
tamaranim1 [39]

ANSWER

The required equation is:

9 {x}^{2}  - 25{y}^{2}  + 250y  - 85 0=0

EXPLANATION

The given equation is

9 {x}^{2}  - 25 {y}^{2}  = 225

Dividing through by 225 we obtain;

\frac{ {x}^{2} }{25}  -  \frac{ {y}^{2} }{9}  = 1

This is a hyperbola that has it's centre at the origin.

If this hyperbola is translated so that its center is now at (0,5).

Then its equation becomes:

\frac{ {(x - 0)}^{2} }{25}  -  \frac{ {(y - 5)}^{2} }{9}  = 1

We multiply through by 225 to get;

9 {x}^{2}  - 25( {y - 5})^{2}  = 225

We now expand to get;

9 {x}^{2}  - 25( {y}^{2} - 10y + 25 )= 225

9 {x}^{2}  - 25{y}^{2}  + 250y  - 6 25 = 225

The equation of the hyperbola in general form is

9 {x}^{2}  - 25{y}^{2}  + 250y  - 85 0=0

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Does the question start with how many were in the bag originally?

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The two posts are parallel lines. The ground is a transversal.

The angles measuring 4x and 75 are same side interior angles, so they are supplementary. Their measures add up to 180.

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If one number is the multiple of another number, then the L.C.M. will be the smaller number (the number whose multiple the other number is).

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