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3 years ago

1 + 2b – 13 = 12 – 4b – 2b for b

Mathematics

2 answers:

Marysya12 [62]3 years ago

6 0

The answer is b=3 for your problem

Andrew [12]3 years ago

5 0

Remember you can do anything to an equation as long as you do it to both sides

1+2b-13=12-4b-2b
1-13+2b=12-6b
-12+2b=12-6b
add 6b both sides
-12+6b+2b=12+6b-6b
-12+8b=12+0
-12+8b=12
add 12 both sides
12-12+8b=12+12
0+8b=24
8b=24
divide both sides by 8
(8b)/8=24/8
(8/8)b=3
1b=3
b=3

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Answer:

Step-by-step explanation:

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3 years ago

Mrs dayson diveded her collection of 52 glass bear into equal groups sha had 1 bear left over how manny groups did Mrs dayson ma

lisov135 [29]

Answer:

Step-by-step explanation:

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3 years ago

Answer and explanation please?

nignag [31]

The answer would be A. m= -3/5 and b=-4/5
"m= -5-1 divided by 7--3
or, -6/10
or, -3/5.

to find the (B)

(-3,1). y=mx+b or 1=-3/5 × -3+b, or solving for b: b=1-(-3/5)(-3). b=-4/5.(7,-5). y=mx+b or -5=-3/5 × 7+b, or solving for b: b=-5-(-3/5)(7). b=-4/5.See! In both cases we got the same value for b. And this completes our problem.

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Source: webmath

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3 years ago

Given f (x)=2x-5x-3 and g (x)=2x^2+x what is (f/g)(x)

Rufina [12.5K]

ANSWER

$( \frac{f}{g} )(x ) = \frac{x - 3}{x} \: where \: \: x \ne0, - \frac{1}{2}$

EXPLANATION

Given:

$f(x) = 2 {x}^{2} - 5x - 3$

and

$g(x) = 2 {x}^{2} + x$

Then,

$( \frac{f}{g} )(x ) = \frac{f(x)}{g(x)}$

Substitute the given functions;

$( \frac{f}{g} )(x ) = \frac{2 {x}^{2} - 5x - 3}{2 {x}^{2} + x}$

Factor

$( \frac{f}{g} )(x ) = \frac{2 {x}^{2} - 6x + x - 3 }{x(2x + 1)}$

$( \frac{f}{g} )(x ) = \frac{2x(x - 3) +1 (x - 3)}{x(2x + 1)}$

$( \frac{f}{g} )(x ) = \frac{(2x + 1)(x - 3) }{x(2x + 1)}$

Cancel the common factors.

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3 years ago

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4 years ago