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3 years ago

14

Lauren has 4 3/8 cups of flour.Each batch of her pancake batter needs 1 1/4 cups of flour.How many batches of her batter can she

make?

1 answer:

GuDViN [60]3 years ago

5 0

She can make 3 batches. 3 batches will take 3 3/4 cups. If she made 4 it would take 5 cups

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Jessica is deciding on her schedule for next semester. She must take each of the following classes: English 101, Spanish 102, Bi

user100 [1]

Just a random guess 22,275 tell me if it right

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2 years ago

How long is a elaphants head

sergejj [24]

Answer: Depends on the elephant ;)

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2 years ago

Marissa bought 12.8 pounds of potatoes at $1.35 per pound how much did Marissa spend for the potatoes? Explain.

Yuri [45]

17.28

1.35 x 12.8 = 17.28

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1 year ago

Write the equation for a parabola with a focus at ( 7, 2) and a directrix at y = -2<br> y = ?

horrorfan [7]

A parabola with an equation, y2 = 4ax has its vertex at the origin and opens to the right.
It's not just the '4' that is important, it's '4a' that matters.
This type of parabola has a directrix at x = -a, and a focus at (a, 0). By writing the equation as it is, the position of the directrix and focus are readily identifiable.
For example, y2 = 2.4x doesn't say a great deal. Re-writing the equation of the parabola as y2 = 4*(0.6)x tells us immediately that the directrix is at x = -0.6 and the focus is at (0.6, 0)

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2 years ago

Solve the given differential equation by using an appropriate substitution. The DE is a Bernoulli equation.

Mama L [17]

Multiplying both sides by $y^2$ gives

$xy^2\dfrac{\mathrm dy}{\mathrm dx}+y^3=1$

so that substituting $v=y^3$ and hence $\frac{\mathrm dv}{\mathrm dv}=3y^2\frac{\mathrm dy}{\mathrm dx}$ gives the linear ODE,

$\dfrac x3\dfrac{\mathrm dv}{\mathrm dx}+v=1$

Now multiply both sides by $3x^2$ to get

$x^3\dfrac{\mathrm dv}{\mathrm dx}+3x^2v=3x^2$

so that the left side condenses into the derivative of a product.

$\dfrac{\mathrm d}{\mathrm dx}[x^3v]=3x^2$

Integrate both sides, then solve for $v$ , then for $y$ :

$x^3v=\displaystyle\int3x^2\,\mathrm dx$

$x^3v=x^3+C$

$v=1+\dfrac C{x^3}$

$y^3=1+\dfrac C{x^3}$

$\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}$

6 0

3 years ago