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vichka [17]
3 years ago
5

The mean heigh of American Males is 69.5 inches. The height of the 43 male presidents have a mean 70.78 inches and a standard de

viation of 2.77 inches. Treating the 43 presidents as a simple random sample, determine if there is evidence to suggest that the US presidents are taller than the average American male. Use the a= 0.05 level of significance.
Mathematics
1 answer:
Arisa [49]3 years ago
4 0

Answer:

There is sufficient statistical evidence to suggest that the US presidents are taller than the average American male

Step-by-step explanation:

The given parameters are;

The mean height of American Males, μ = 69.5 inches

The mean height of 43 male presidents, \overline x = 70.78

The standard deviation, s = 2.77 inches

The number of male presidents = 43

The null hypothesis; H₀ μ = \overline x

The alternative hypothesis; Hₐ μ ≠ \overline x

The significance level, α = 0.05

The t test for the sample with unknown population standard deviation is given as follows;

t=\dfrac{\bar{x}-\mu }{\dfrac{s }{\sqrt{n}}}

Therefore, we have;

t=\dfrac{70.78-69.5 }{\dfrac{2.77 }{\sqrt{43}}} \approx 3.0302

The degrees of freedom, df = n - 1 = 43 - 1 = 42

The critical 't' value = 2.0181

Therefore, given that the t test value is larger than the critical-t, we reject the null hypothesis, therefore, there is sufficient statistical evidence to suggest that the US presidents are taller than the average American male

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The given question is incomplete , the complete question is

A professional bowler wanted to gather data about the cost of local bowling leagues in the area. After collecting and plotting the data, it was determined that the average bowling league consists of a one-time registration fee and a monthly fee modeled by the equation y = 12x + 30.

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(c) The slope is 12. Starting at $30, the cost will increase by $12 per month.

(d) The slope is 12. Starting at $30, the cost will decrease by $12 per month.

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