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Lostsunrise [7]
3 years ago
15

Please Help!!!!!!!!!!!!!!!

Mathematics
1 answer:
melisa1 [442]3 years ago
3 0

Answer:X=4

Step-by-step explanation:

Congruent triangles method

AB/DB=BC/EC

10-x+x/10-x=3+2/3

10/10-x=5/3

30=50-5x

30-50=-5x

-20=-5x

X=4

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Need answer fast with all the steps included please
marysya [2.9K]

Answer:

(\frac{6x^2y}{5})

Step-by-step explanation:

Given

\frac{(2x)(3x^3y^2)}{5x^2y}

Required

Solve

Open the brackets

\frac{(2x)(3x^3y^2)}{5x^2y} = \frac{(2x*3x^3y^2)}{5x^2y}

\frac{(2x)(3x^3y^2)}{5x^2y} = \frac{(6x^4y^2)}{5x^2y}

Apply law of indices:

\frac{(2x)(3x^3y^2)}{5x^2y} = \frac{(6x^{4-2}y^{2-1})}{5}

\frac{(2x)(3x^3y^2)}{5x^2y} = \frac{(6x^2y)}{5}

\frac{(2x)(3x^3y^2)}{5x^2y} = (\frac{6x^2y}{5})

6 0
3 years ago
Someone please help me
Whitepunk [10]

Since the exponent is on the outside of the paranthesis, you'd have to multiply it by everything on the inside: a^m x b^m

5 0
4 years ago
Find the value of the lettered angles in each of the following ( see image ).
Arisa [49]

Step-by-step explanation:

here's the solution :-

1.) =》f = 90°

( because angle made by diameter on circumference of the circle measures 90° )

2.) =》here,

g + f + 56° = 180°

( because the sum of all interior angles of the triangle measures 180° )

=》g + 90° + 56° = 180°

=》g + 146° = 180°

=》g = 180° - 146°

=》g = 34°

3.) h = 56°

( since, they form alternate interior pair which are equal )

4 0
3 years ago
Read 2 more answers
Given: 3x < 3.
mamaluj [8]
<span>Divide by 3 and get x<1, so the answer is {x | x < 1}

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
4 0
3 years ago
Read 2 more answers
What’s the length of the missing leg?!
posledela

<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>2</em><em> </em><em>m</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em>

<h3><em>Good</em><em> </em><em>luck</em><em>.</em><em>.</em><em>.</em></h3>

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3 years ago
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