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pshichka [43]
3 years ago
9

Doe anyone know this? At least someone have to

Mathematics
1 answer:
Paul [167]3 years ago
4 0

Answer:

While I will not give you an answer, I will tell you how to find it. Don't get scared! I promise it's not complicated. You basically only need to do subtraction.

Concept Explanation:

Okay, so let's start off by defining "complement" and "supplement":

"Complement" - <em><u>complementary angles</u></em>: two angles whose sum equals 90°

"Supplement" - <u><em>supplementary angles</em></u>: two angles whose sum equals 180°

So, this question is asking you what the <u>other angle</u> is. Based on whether they ask you for the <em>complement</em> or <em>supplement</em>, you only need to subtract the first angle they give you from 90° (if it's asking for the complement) or 180° (if it's asking you for the supplement).

Here are some examples if you're still confused!

--------------------------------------------------------------------------------------------------------------

- What is the complement of a 32° angle?

↓

Since they're asking for the <u>complement</u>, we will subtract 32° (the angle they give us) from 90° (because it's a <u>complement</u>)

↓

90 - 32 = 58

↓

So our answer is: <u>58°</u>

--------------------------------------------------------------------------------------------------------------

Now let's do a supplement one.

--------------------------------------------------------------------------------------------------------------

- What is the supplement of an 84° angle?

↓

Because they're asking for the <u>supplement</u>, we will subtract 84° (the angle they give us) from 180° (because it's a <u>supplement</u>)

↓

180 - 84 = 96

↓

Then our answer will be: <u>96°</u>

--------------------------------------------------------------------------------------------------------------

That's all! It's just some subtraction once you know what the vocabulary means. Please comment if you have any other questions.

If you want me to check your answers once you try your problem, I can do that as well!

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