The correct answer is C. It continues to eat the amount of food it does normally.
When rat's ventromedial nucleus is destroyed the rat will become more hyper physics and it continues to eat until it has doubled its normal weight.
Ventromedial nucleus of hypothalamus is termed as nucleus of hypothalamus.
It is a distinct morphological nucleus which involved in terminating hunger, fear, sexual activity and thermoregulation.
Ventromedial nucleus of hypothalamus is divided into subdivisions. For example, dorsomedial, ventrolateral, central and anterior. VMN is most commonly associated with satiety. In rats ventromedial nucleus is caused by over-eating and obesity.
Answer:1. Pyruvate carboxylase
2. Phosphoenol pyruvate carboxy kinase
Explanation:
The conversion of pyruvate to phosphoenol pyruvate is catalyzed by two enzymes Pyruvate carboxylase and phosphoenol pyruvate carboxy kinase
1. Pyruvate carboxylase reaction
Pyruvate in the cytoplasm enters the mitochondria. Then, carboxylase of pyruvate to oxaloacetate is catalysed by a mitochondrial enzyme, pyruvate carboxylase. It needs the co-enzymes biotin and ATP.
The oxaloacetate formed has to be transported from the mitochondrial to the cytosol because further reaction of gluconeogenesis are taking place in cytosol.
2. Phoaphoenol pyruvate carboxy kinase (PEPCK)
In the cytoplasm, PEPCK enzyme then converts oxaloacetate to phoaphoenol pyruvate by removing a molecule of CO2. GTP or ITP donates the phosphate group.
The net effect of these two reactions is the conversion of pyruvate to phoaphoenol pyruvate. This circumverts the irreversible step in glycolysis catalyzed by pyruvate kinase (step 9 if glycolysis)
Answer:
The sodium-potassium pump is an active transporter because it needs to move sodium and potassium ions against the concentration gradient.
Explanation:
You have to think of it as outside vs inside the cell.
Outside the cell, you have 5mM K and 150mM Na. Inside the cell, you have 100mM K and 10mM sodium. Without the transporter then the ions would go from greater concentration to lower concentration. Energy keeps the ions going from the way they would naturally happen.
Answer:
as a dimer consisting of two identical monomers (80 kDa subunits) that are packed together via hydrophobic interactions
Explanation:
SDS-PAGE (sodium dodecyl sulphate–polyacrylamide gel electrophoresis), is an electrophoretic methodology used to separate proteins that have a molecular weight between 5 to 250 kDa. SDS is a well-known ionic detergent that is able to break hydrophobic interactions and hydrogen bonds. Moreover, size-exclusion chromatography is a filtration technique that separates molecules in solution according to their molecular size. In this case, SDS-PAGE showed that the target protein is composed of two identical subunits (monomers) of 80 kDa each, which were separated by the detergent and formed one single band in the SDS-PAGE gel.
Answer:
The correct answer is 4,960,000
Explanation:
If a yeast cell divides into two yeast cells in 120 minutes that means a yeast cell needs 2 hours to get double. So according to the question 2 hours ago a yeast colony consisted of 310,000 cells that means the present colony should have 620,000 cells.
So after six hours from now, this population will divide three times in six hours because the generation time of yeast cell is 2 hour and each time the number of cells will double.
Therefore, in first time the number will increase to 1,240,000(620000*2), the second time the number will increase to 2,480,000(1240000*2) and after final division, the number will be 4,960,000(2480000*2).
Therefore after 6 hours from now, the approximate number of yeast cells will be 4,960,000.
