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Jlenok [28]
3 years ago
12

How to multiply and divide algebraic fractions

Mathematics
1 answer:
Alex787 [66]3 years ago
5 0

Answer:

Step-by-step explanation:

Multiplying two algebraic fractions produces a new algebraic fraction. Multiply the two numerators to get the new numerator and multiply the two denominators to get the new denominator. Then simplify by reducing the new fraction to lowest terms.

for example:

\frac{x}{y} \\×\frac{a}{b} = \frac{xa}{yb}

Division of algebraic fractions

The procedure for dividing algebraic fractions is the same as the procedure for dividing common fractions.  Replace the division by a fraction by the multiplication by the reciprocal of that fraction, like this. Then carry out the multiplication of the two fractions as described above.

for example:

\frac{\frac{a}{b} }{\frac{x}{y} }

can be written as

\frac{a}{b}×\frac{x}{y}= \frac{ax}{by}

hope this answer helped you. pls mark as brainliest.

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The polynomial x^2+3x-1 is a factor of x^4+3x^3-2x^2-3x+1 true or false?
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Answer:

Yes, it is true that x^2+3x-1  is a factor of x^4+3x^3-2x^2-3x+1.

Step-by-step explanation:

Let us try to factorize x^4+3x^3-2x^2-3x+1

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Let us try to make a whole square of the given terms:

\Rightarrow (x^2)^2-2\times x^2 \times 1+1^2+3x^3-3x\\\Rightarrow (x^2-1)^2+3x^3-3x\\

--------------

Formula used above:

a^{2} -2 \times a \times b +b^{2}  = (a-b)^2

In the above equation, we had a = x, b = 1.

--------------

Further solving the above equation, taking 3x common out of 3x^3-3x

\Rightarrow (x^2-1)^2+3x(x^2-1)\\

Taking (x^{2} -1) common out of the above term:

\Rightarrow (x^2-1)((x^2-1)+3x)\\\Rightarrow (x^2-1)(x^2+3x-1)

So, the two factors are (x^2-1)\ and\ (x^2+3x-1).

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