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3 years ago

12

A baseball is launched horizontally from a height of 1.8 mThe baseball travels 0.5 m before hitting the ground. How fast is the

baseball moving, rounded to the nearest hundredth? m/s

2 answers:

Svetradugi [14.3K]3 years ago

8 0

0.82 is the right answer from e2020

Reptile [31]3 years ago

6 0

T=((2*1.8)/10)^(1/2)
t=.6sec
v=vintial+at
v=0-10 m/s^2(.6s)
v=-6m/s

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A 3.5 kW drill transfers 5 000 kJ of kinetic energy during 15 seconds of use. What is the percentage efficiency of the drill?

Marizza181 [45]

Answer:

1.04%

Explanation:

Given that,

The power of drill = 3.5 kW = 3500 W

Transferred kinetic energy = 5000 kJ during 15 seconds of use.

We need to find the percentage efficiency of the drill. It can be given by :

$\eta=\dfrac{P_o}{P_i}\times 100$

Where

Po and Pi are output and input powers.

$P_o=\dfrac{5000\times 10^3}{15}\\\\=3.34\times 10^5\ W$

So,

$\eta=\dfrac{3500}{3.34\times10^{5}}\times100\\\\=1.04\%$

So, the percentage efficiency of the drill is 1.04%.

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4. Calculate the kinetic energy of a 4.7 kg object moving at a speed of 7 m/s. SHOW YOUR WORK

SashulF [63]

Answer:

$\boxed {\boxed {\sf 115.15 \ J}}$

Explanation:

Kinetic energy is the energy an object possesses due to motion. It is calculated with the following formula.

$E_K= \frac{1}{2} mv^2$

The mass of the object is 4.7 kilograms. The velocity of the object is 7 meters per second.

m= 4.7 kg
v= 7 m/s

Substitute the values into the formula.

$E_K= \frac{1}{2} (4.7 \ kg)(7 \ m/s)^2$

Solve the exponent.

(7 m/s)²= 7 m/s * 7 m/s = 49 m²/s²

$E_K= \frac{1}{2} (4.7 \ kg)(49 \ m^2/s^2)$

Multiply the numbers together.

$E_K = 2.35 \ kg * 49 \ m^2/s^2$

$E_K= 115.15 \ kg*m^2/s^2$

Convert the units. 1 kilogram square meter per square second is equal to 1 Joule.

$E_K= 115.15 \ J$

The object has <u>115.15 Joules</u> of kinetic energy.

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Explanation:

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