Answer:
303 Ω
Explanation:
Given
Represent the resistors with R1, R2 and RT
R1 = 633
RT = 205
Required
Determine R2
Since it's a parallel connection, it can be solved using.
1/Rt = 1/R1 + 1/R2
Substitute values for R1 and RT
1/205 = 1/633 + 1/R2
Collect Like Terms
1/R2 = 1/205 - 1/633
Take LCM
1/R2 = (633 - 205)/(205 * 633)
1/R2 = 428/129765
Take reciprocal of both sides
R2 = 129765/428
R2 = 303 --- approximated
Answer:
(4) weight
Explanation:
The centripetal force acting on the space shuttle in orbit is given by:

where
m is the mass of the shuttle
v is the tangential speed of the shuttle
r is the radius of its circular orbit
When the shuttle orbits the Earth, the centripetal force that keeps the shuttle in circular motion is given by the gravitational attraction between the shuttle and the Earth, which corresponds to the weight of the shuttle, and it is given by:

where
G is the gravitational constant
M is the Earth's mass
And this force, therefore, corresponds to the centripetal force.
Answer:1 because
Explanation: it’s pointing to the earth and gravity
Pulls things down to earth
Answer: equation for the reaction is given below
PCL2+PCL3=PCL5
Where pcl2=0.40atm,pcl3=0.27atm
Pcl5=0.0029atm
Using ∆G=-RTin(PCL5/PCl2*PCL3)
Where R=8.314J/K/mol and T=298K
∆G=-8.314*298in(0.0029/0.40*.27)
∆G=8962.6J/mol
Explanation: