Solve for x: 3(x + 1) = −2(x − 1) + 6.

Mathematics

2 answers:

Firlakuza [10]2 years ago

8 0

The answer would be x=1

Katen [24]2 years ago

4 0

First, distribute the numbers

3(x+1) = -2(x-1) +6
3x+3 = -2x+2+6
3x+3 = -2x+8
Subtract 3 from the left to get rid of it and move it to the right
(3x+3)-3 = (-2x+8)-3
3x= -2x+5
Add 2x from the right to get rid of it and move it to the left.
(3x)+2x = (-2x+5) +2x
5x = 5
Divide both sides by 5
5x/5 = 5/5
x = 1

You might be interested in

Eight members of a school marching band are auditioning for 3 drum major

Doss [256]

Answer:

Step-by-step explanation:

7 0

2 years ago

Matrix multiplication was used to encode a message using the given encoding matrix: [i 47 A=1 |-1 -3] The original message was c

nadya68 [22]

Answer:

$A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right]$ message SHOW_ME_THE_MONEY_

Step-by-step explanation:

The matrix

$A=\left[\begin{array}{cc}1&4\\-1&-3\end{array}\right]\rightarrow |A|=(1 \times -3)-(-1\times 4)=1\\\rightarrow A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] \\$

We can check that in fact A*A^⁻1=I_2 the identity matrix of size 2 x 2.

Now the message was divided in 1 x 2 matrices, then we have that the sequence given is the result of multiplying m by A, so to get m again we multiply now by A^⁻1. and we get the next table

Encoded message Decoded message message in letters by association

11 52 19 8 S H

-8 -9 15 23 O W

-13 -39 0 13 _ M

5 20 5 0 E _

12 56 20 8 T H

5 20 5 0 E _

-2 7 13 15 M O

9 41 14 5 N E

25 100 25 0 Y _

Then the message decoded is SHOW_ME_THE_MONEY_