Answer:
Area covered by the fences will be 16.1 unit²
Step-by-step explanation:
Let the first parabola is represented by the function f(x) = 6x²
and second parabola by g(x) = x² + 9
point of intersection of the graphs will be determined when f(x) = g(x)
6x² = x² + 9
5x² = 9
x² = 1.8
x = ± 1.34
Now we will find the area between these curves drawn on the graph.
Area = ![\int_{-1.34}^{1.34}[f(x)-g(x)]dx=\int_{-1.34}^{1.34}[6x^{2}-(x^{2}+9)]dx](https://tex.z-dn.net/?f=%5Cint_%7B-1.34%7D%5E%7B1.34%7D%5Bf%28x%29-g%28x%29%5Ddx%3D%5Cint_%7B-1.34%7D%5E%7B1.34%7D%5B6x%5E%7B2%7D-%28x%5E%7B2%7D%2B9%29%5Ddx)
= 
= ![[\frac{5}{3}x^{3}-9x]_{-1.34}^{1.34}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B5%7D%7B3%7Dx%5E%7B3%7D-9x%5D_%7B-1.34%7D%5E%7B1.34%7D)
= ![[\frac{5}{3}(-1.34)^{3}-9(-1.34)-\frac{5}{3}(1.34)^{3}+9(1.34)]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B5%7D%7B3%7D%28-1.34%29%5E%7B3%7D-9%28-1.34%29-%5Cfrac%7B5%7D%7B3%7D%281.34%29%5E%7B3%7D%2B9%281.34%29%5D)
= ![[-4.01+12.06-4.01+12.06]](https://tex.z-dn.net/?f=%5B-4.01%2B12.06-4.01%2B12.06%5D)
= 16.1 unit²
Answer:
Step-by-step explanation:
-Probability is the likelihood of an event occurring.
-The total number of events is:
-The total number of blue events is:
#Probability of a blue is thus calculated as:
Hence, the probability of choosing a blue marble at random is 37.5%
$65.91 should be the account balance at the end of the month
Answer: B. Graph of 2 lines that intersect at one point. Both lines are solid. One line passes through (-2,2) and (0,3) and is shaded below the line.
y < = 1/2x + 3...(-2,2) y < = 1/2x + 3....(0,3)
2 < = 1/2(-2) + 3 3 < = 1/2(0) + 3
2 < = -1 + 3 3 < = 0 + 3
2 < = 2 (correct) 3 < = 3 (correct)
The other line passes through points (0,1) and (1,-2) and is shaded above the line.
y > = -3x + 1...(0,1) y > = -3x + 1...(1,-2)
1 > = -3(0) + 1 -2 > = -3(1) + 1
1 > = 0 + 1 -2 > = -3 + 1
1 > = 1 (correct) -2 > = -2 (correct)
Answer:
6.
Step-by-step explanation:
1) OA=d/2=20/2=10;
2) AB=AC/2=16/2=8;
