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8_murik_8 [283]
3 years ago
14

Sally is buying new school supplies. She used a 15% off coupon on a set of markers that was originally $3.00. She also bought so

me paper that was 20% off. In total, Sally spent $5.35 after using her coupons. How much was the original price of the paper?
Mathematics
1 answer:
fenix001 [56]3 years ago
6 0
The original price of the paper was $3.50

I hope this helps! let me know if you need help with anything else! I'd be happy to help you in anyway I can! :)
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PLEASE HELP!! I’LL MAKE YOU BRAINIEST!
Leokris [45]

Answer:

1. Markup: $2.70, Retail: $20.70

2. Markup: $9.45, Retail: $31.95

3. Markup: $25.31, Retail: $59.00

4. Markup: $24.75, Retail: $99.74

5. Markup: $48.60, Retail: $97.20

6. Markup: $231.25, Retail: $416.25

Step-by-step explanation:

To get the markup price of an item, multiply it by the markup percentage as a decimal. To get the decimal of a percentage, divide the number by 100. For example, 15% would be 0.15. And then to find how much the item has been marked up by, multiply the current price by the decimal.

$18 * 0.15 = $2.70

So $2.70 is the markup. To find the retail price, you need to add the markup price to the current price given.

$18 + $2.70 = $20.70

So your retail price is $20.70. Repeat these steps for each question to get the answers above.

Hope this helps.

7 0
3 years ago
Use the zero product property to find the solutions to the equation x2 + x – 30 = 12.
Butoxors [25]

Answer:

x= 6, -7

Step-by-step explanation:

3 0
3 years ago
Could someone help me with number 19
azamat

Solving #19

<u>Take y-values from the graph</u>

  • a) (g·f)(-1) = g(f(-1)) = g(1) = 4
  • b) (g·f)(6) = g(f(6)) = g(2) = 2
  • c) (f·g)(6) = f(g(6)) = f(5) = 1
  • d) (f·g)(4) = f(g(4)) = f(2) = -2
8 0
3 years ago
Find the value of X in each of the given triangles.​
ki77a [65]

<DSR + <SRD + <RDS = 180° (Angle sum property)

2x + x +3x = 180°

6x = 180°

x = 180°/6

x = 30°

So, <SRD = x = 30°

<RDS = 3x = 3(30°) =90°

<DSR = 2x = 2(30°) = 60°

Hope it helps !

✌️

Jai hind !

8 0
3 years ago
Read 2 more answers
Limit xtens to 0 x^2logx^2 what is the ans of interminate forms?
GarryVolchara [31]

Rewrite the limit as

\displaystyle\lim_{x\to0}x^2\log x^2=\lim_{x\to0}\frac{\log x^2}{\frac1{x^2}}

Then both numerator and denominator approach infinity (with different signs, but that's not important). Applying L'Hopital's rule, we get

\displaystyle\lim_{x\to0}\frac{\log x^2}{\frac1{x^2}}=\lim_{x\to0}\frac{\frac2x}{-\frac2{x^3}}=\lim_{x\to0}-x^2=\boxed{0}

7 0
3 years ago
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