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storchak [24]
1 year ago
5

Evaluate the following functions for the given value. 20. g(x) = x-3/2x+1 ; -1

Mathematics
1 answer:
Fudgin [204]1 year ago
4 0

The value of the function g(x) = x -3/2x + 1 for x = -1 is g(-1) = 4

<h3>How to evaluate the functions for the given value?</h3>

The function is given as:

g(x) = x -3/2x + 1

The value is given as:

x = -1

Substitute the known values in the above equation

i.e. we substitute the -1 for x in the above equation

So, we have:

g(-1) = -1 -3/2(-1) + 1

Expand the bracket

g(-1) = -1 -3/-2 + 1

Evaluate the sum and the difference

g(-1) = -4/-1

Evaluate the quotient

g(-1) = 4

Hence, the value of the function g(x) = x -3/2x + 1 for x = -1 is g(-1) = 4

So, the complete parameters are:

g(x) = x -3/2x + 1

x = -1

g(-1) = 4

Read more about functions at:

brainly.com/question/2328150

#SPJ1

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2 years ago
A​ half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches. Assume that the heights of​
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99.5% of all samples of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches.

Step-by-step explanation:

We are given that a half-century ago, the mean height of women in a particular country in their 20's was 64.7 inches. Assume that the heights of​ today's women in their 20's are approximately normally distributed with a standard deviation of 2.07 inches.

Also, a samples of 21 of​ today's women in their 20's have been taken.

<u><em /></u>

<u><em>Let </em></u>\bar X<u><em> = sample mean heights</em></u>

The z-score probability distribution for sample mean is given by;

                          Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

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            \sigma = standard deviation = 2.07 inches

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches is given by = P(\bar X \geq 65.86 inches)

  P(\bar X \geq 65.86 inches) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{65.86-64.7}{\frac{2.07}{\sqrt{21} } } ) = P(Z \geq -2.57) = P(Z \leq 2.57)

                                                                        = <u>0.99492  or  99.5%</u>

<em>The above probability is calculated by looking at the value of x = 2.57 in the z table which has an area of 0.99492.</em>

<em />

Therefore, 99.5% of all samples of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches.

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