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Rainbow [258]
3 years ago
9

Pre-Calc Please help with the question highlighted in red

Mathematics
1 answer:
ololo11 [35]3 years ago
4 0
Believe it or not, this is the second version of Q is very similar to the first, even though it doesn't really look like it. We can represent the second version as a * (1 + r)^t

See the similarity between this and the first version? Thus, we can represent what is given in the problem as:
Q = a * b^t  = a * (1 + r)^t

Thus, b = 1 + r. Since b = 0.8, we can find r.
0.8 = 1 + r
r = -0.2, or r = -20%.
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I need help on a question
schepotkina [342]

Given the figure of a regular pyramid

The base of the pyramid is a hexagon with a side length = 6

The lateral area is 6 times the area of one of the side triangles

So, the side triangle has a base = 6

The height will be:

\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}

so, the lateral area =

6\cdot\frac{1}{2}\cdot6\cdot\sqrt[]{63}=18\sqrt[]{63}

3 0
1 year ago
A personnel director in a particular state claims that the mean annual income is the same in one of the​ state's counties​ (Coun
Shalnov [3]

Answer:

a) The hypothesis that the mean annual income is the same could not be rejected. There is no enough evidence to claim they are different.

b) The critical values for this two-sided test are t=±1.711.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>(a) Identify the claim and state  H0  and  Ha. </em>

<em> Which is the correct claim​ below?</em>

<em>(b) Find the critical​ value(s) and identify the rejection​ region(s). </em>

<em> Enter the critical​ value(s) below.</em>

We have an hypothesis test on the difference of two means.

The null and alternative hypothesis are:

H_0: \mu_a-\mu_b=0\\\\H_a: \mu_a-\mu_b\neq 0

The claim of the alternative hypothesis is that the mean annual income is different in County A and County B.

The null hypothesis is that the mean annual income is equal in both counties.

The significance level is α=0.10.

The sample from County A has a mean of S40,400, a s.d. of $8,700 and a sample size of 18 residents.

The sample from County B has a mean of S39,200, a s.d. of $6,000 and a sample size of 8 residents.

The standard error of the difference of means is:

\sigma_d=\sqrt{\frac{\sigma_a^2}{n_a}+\frac{\sigma_b^2}{n_b}}=\sqrt{\frac{8700^2}{18}+\frac{6000^2}{8}}=\sqrt{8705000}=2950

The degrees of freedom are:

df=n_a+n_b-2=18+8-2=24

Then, the test statistic is:

t=\frac{\Delta M-\Delta \mu}{\sigma_d} =\frac{(40,400-39,200)-0}{2950} =\frac{1200}{2950}=0.407

For a statistic t=0.407, and df=24, the P-value is P=0.69. As the P-value is bigger than the significance level, the null hypothesis failed to be rejected.

If we would use the critial value approach, we would have to calculate the critical values for t, for df=24, two sided test and α=0.10.

The critical values, looking in a table, are t=1.711.

5 0
2 years ago
Help please desprate will mark brainliest
tester [92]

Answer:

-1.5

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
I need help with this ASAP
SOVA2 [1]

Answer:

Step-by-step explanation:

1 and 2 are linear pairs

1 and 3 are verticle

4 and 5 are adjacent

5 0
3 years ago
Read 2 more answers
0.3(y+2)=1.7+(8-y) solve the following equation​
Andrei [34K]

Answer:

y = 7

Step-by-step explanation:

0.3y+0.6 = 9.7 - y

0.3y+y = 9.7 -0.6

1.3y = 9.1

y= 7

sorry it had an error

6 0
2 years ago
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