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Murljashka [212]
2 years ago
6

The diagram shows a circle with centre O. Points A , B, C and D all lie on the circumference of the circle.

Mathematics
1 answer:
kykrilka [37]2 years ago
7 0

Answer:

The puck travels in a circular path of radius 0.25 m. ... C. away from the centre. D. ... If the speed of the mass at the top of the circle is 3.6

Step-by-step explanation:

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Beth purchased a computer, and its value depreciated exponentially each year. Beth will sketch a graph of the situation, where x
Katyanochek1 [597]

What is x?

It is the number of years since purchase. Can this be negative?

NO! Years cannot be negative. So we disregard negative x-axis.


What is y?

It is the value of the computer at that year. A computer starts off with a positive value (y axis) and depreciates to 0 after some years. Can this be negative?

NO! At 0 value, the computer is worth nothing! There is nothing known as <em>negative </em>value. So we disregard negative y-axis.


The graph that Beth will sketch will have to be in the 1st quadrant (positive x-axis & positive y-axis).

ANSWER: Quadrant I only

3 0
3 years ago
Which scatterplot shows a nonlinear association?
Ad libitum [116K]

Answer:

d

Step-by-step explanation:

it's the only one that isn't a trend

8 0
3 years ago
Read 2 more answers
Select 3 ratios that are equivalent to 4 : 3
Bad White [126]

Answer:

3 ratios that are equivelent to 4 : 3

8 : 6

20 : 15

and 12 : 9

Step-by-step explanation:

8 0
3 years ago
To rent a jet ski at Sam’s costs $25 plus $3 per hour. At Claire’s, it costs $7 plus $6 per hour. At how many hours will the ren
skad [1K]

Answer:

 The number of hours that the cost of renting a ski jet will become equal in both shops is 6(hours)

Step-by-step explanation:

  Extracting the key information from the question:-

*** Renting a jet ski at Sam's establishment costs $25 and additional $3 per hour.

*** Again, it costs $7 and additional $6 per hour to rent a jet ski at Claire's establishment.

*** We are required to find out the number of hours that the rental cost of jet ski at both shops will be the same.

  What we are basically required to do is to find that number of hours that you can rent a jet ski and you wouldn't need to worry about the shop that renting it's jet ski will be more affordable in because the cost will be the same in both establishment when renting the jet ski at a particular number of hours.

    For example, in that number of hours, the cost in Sam's shop and Claire's shop will now both be say, $50.

   Since it costs a down payment of $25 plus additional $3 for each hour we make use of the jet ski at Sam's establishment, then the cost of renting a jet ski at Sam's shop for that number of hours that the cost will become equal in both shops is:

  =  25  +  3x

 Again, we are informed that it costs $7 down payment and additional $6 per hour that a jet ski from Claire's establishment will b rented and used. Then the cost of renting a jet ski at Claire's establishment for that number of hours that the cost will become equal in both shops is:

   

       = 7 + 6x

 Since at this unknown number of hours (x hours) the cost of renting a jet ski at Sam's shop will be equal to the cost of renting a jet ski at Claire's establishment, then marrying the equations, we will have:-

25 + 3x = 7 + 6x

We now pair like terms

6x - 3x  = 25 - 7

   3x  =  18

    x  = 18/3

    x  = 6

  Therefore, that number of  hours that the cost of renting a jet ski will become equal in both Sam's and Claire's establishment is 6 hours.

   

3 0
3 years ago
Which equation can be solved by using this expression?
Marat540 [252]

<u>Answer:</u>

The correct answer option is B. 2 = 3x + 10x^2

<u>Step-by-step explanation:</u>

We are to determine whether which of the given equations in the answer options can be solved using the following expression:

x=\frac{-3 \pm\sqrt{(3)^2+4(10)(2)} }{2(10)}

Here, a = 10, b = 3 and c=-2.

These requirements are fulfilled by the equation 4 which is:

12=3x+10x^2

Rearranging it to get:

10x^2+3x-2=0

Substituting these values of a,b,c in the quadratic formula:

x= \frac{-b \pm \sqrt{b^2-4ac} }{2a}

x= \frac{-3 \pm\sqrt{(3)^2-4(10)(-2)} }{y}

3 0
3 years ago
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