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Flauer [41]
3 years ago
15

Fill in both boxes I’m stuck

Mathematics
1 answer:
kozerog [31]3 years ago
5 0

Answer:

y = (3c-2)/b

Step-by-step explanation:

(by+2)/3 = c

multiply by 3 both side

by+2 = 3c

subtracting 2 from both side

by = 3c - 2

dividing by b both side

y = (3c-2)/b

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Steven buys 2.32 pounds of trail mix and twice as many pounds of dressed fruit. What is the total?
kati45 [8]

Answer:

4.64

Step-by-step explanation:

You multiply 2.32 by 2

2.32*2 = 4.64

6 0
3 years ago
I will appreciate your help
KatRina [158]

Answer:

Hello! answer: 252

Step-by-step explanation:

To find parelogram area you do base × height so... 21 × 12 = 252 therefore 252 is the area Hope that helps!

4 0
3 years ago
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PLEASE HELP ILL GIVE BRAINLIEST<br> can someone help me finish this table please
Darya [45]

Answer:

1st box= 6.

2nd box= 4.

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Step-by-step explanation:

8 0
4 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E5_1%20%7B%20%5Cfrac%7BlnR%7D%7B%20R%5E%7B2%7D%20%20%7D%20%5C%2C%20dR%20"
alex41 [277]
Integrate by parts, setting

\begin{matrix}u=\ln R&&\mathrm dv=\dfrac{\mathrm dR}{R^2}\\\mathrm du=\dfrac{\mathrm dR}R&&v=-\dfrac1R\end{matrix}

So the integral is

\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\dfrac{\ln R}R\bigg|_{R=1}^{R=5}+\int_1^5\frac{\mathrm dR}{R^2}
\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\left(\frac{\ln5}5-\frac{\ln1}1)-\frac1R\bigg|_{R=1}^{R=5}
\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\frac{\ln5}5-\left(\frac15-1\right)
\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=\frac15(4-\ln5)
5 0
4 years ago
Find the exact value by using a half-angle identity. sine of five pi divided by twelve
maks197457 [2]

Answer:

cos

(

5

π

12

)

=

√

2

−

√

3

2

Explanation:

By the half angle formula:

XXXX

cos

(

θ

2

)

=

±

√

1

+

cos

(

θ

)

2

If  

θ

2

=

5

π

12

XXXX

then  

θ

=

5

π

6

Note that  

5

π

6

is a standard angle in quadrant 2 with a reference angle of  

π

6

so  

cos

(

5

π

6

)

=

−

cos

(

π

6

)

=

−

√

3

2

Therefore

XXXX

cos

(

5

π

12

)

=

±







⎷

1

−

√

3

2

2

XXXXXXXXXXX

=

±







⎷

2

−

√

3

2

2

XXXXXXXXXXX

=

±

√

2

−

√

3

4

XXXXXXXXXXX

=

±

√

2

−

√

3

2

Since  

5

π

12

<

π

2

XXXX

5

π

12

is in quadrant 1

XXXX

→

cos

(

5

π

12

)

is positive

XXXX

XXXX

XXXX

(the negative solution is extraneous)

answer in pic more explain

3 0
3 years ago
Read 2 more answers
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