Answer:
2 and 3 are correct, not sure if you plan on doing 1, in which case I'd help you
A two-digit number is twice the sum of its digit. If the tens digit is 7 less than the unit digit, find the number.
Let x= the unit digit
Then y= the tens digit
<span>And 10y+x= the number
</span>x+y= the sum of the digits
<span>Now we are told that 10y+x=2(x+y) ------1st equation </span>
<span>We are also told that y=x-7 ----------- 2nd Equation </span>
<span>So our equations to solve are: </span>
(1) 10y+x=2(x+y)
<span>(2) y=x-7
</span>
Hope it helps
Answer:
answer is c
Step-by-step explanation:
Given that: step 1
step 2: subtract 3x both side
Step 3: Add 18 both side:
Step 4: divide both side by 5
Step:6 The value of x is:
x=6
