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3 years ago

6

1080 people attended a basketball game. 594 of the people attending supported the home team,while 486 supported the visiting tea

m. What percentage of people attending the home team?

2 answers:

tester [92]3 years ago

6 0

55% of the people attending are supporting the home team.

svet-max [94.6K]3 years ago

3 0

Answer: the answer is 55

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∡C and ∡D are supplementary angles. If m∡D is nine less than twice m∡C, find m∡D.

Gala2k [10]

Answer:

D is 117

Step-by-step explanation:

Let the measure of angle C be x

The measure of D is 9 less than twice C

Mathematically that is 2x-9

If both are supplementary, they add up to be 180

Thus;

x + 2x - 9 = 180

3x = 180 + 9

x = 189/3

x = 63

Recall;

D = 2x-9= 2(63) -9 = 126 -9 = 117

6 0

3 years ago

Expand to write an equivalent expression -1/2 (-6x+8y) <br><br>(Pleasee help i need an answer rqqqq)

Alik [6]

Answer:

$- \frac{1}{2} ( - 6x + 8y) \\ = \frac{1}{2} (6x - 8y) \\ = 3x - 4y$

6 0

3 years ago

Which value is NOT a solution of 8x3 – 1 = 0?

Tpy6a [65]

<u><em>Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.</em></u>

Answer:

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Step-by-step explanation:

Considering the equation

$8x^3\:-\:1\:=\:0$

Steps to solve the equation

$8x^3-1=0$

$\mathrm{Add\:}1\mathrm{\:to\:both\:sides}$

$8x^3-1+1=0+1$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{Divide\:both\:sides\:by\:}8$

$\frac{8x^3}{8}=\frac{1}{8}$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

As

$\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

$x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}$

So,

$x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$

Therefore,

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Keywords: solution, value

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7 0

3 years ago

Biking at 10 mph, it takes Kristen hour to reach the train station to go to work. Kristen then takes the train to work, and it t

vivado [14]

<span>d = 18 mi is the answer</span>

6 0

3 years ago

Penny has some money. After

kati45 [8]

Answer:

$32

Step-by-step explanation:

The money she spent was $5 on the kitten and if you add $5 to the remaining $27 that is $32

4 0

3 years ago

Read 2 more answers