Answer:
Option 1: CD is a perpendicular bisector of AB
Step-by-step explanation:
Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.
Formula to find slope
Formula to Find Distance between two points
mAB ( represents , Slope of AB )
1. 
2. 
3. 
4. 
5. 
mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is 
Hence CD ⊥ AB
Also
From Point 4 and point 5 above , we see that
AC = CB
Hence CD bisect AB at C, also CD ⊥ AB
There fore
CD is a perpendicular bisector of AB
Therefor option 1 is true
a) plug in x =2700 into the given equation and solve for y
b) plug in y = 43 into the given equation and solve for x
c) plug in y = 0 into the given equation and solve for x
hope this helps.
Answer:
x = ± 
- 3
Explanation:
I'm assuming you want the solutions to that equation, so here goes! (If not, please comment.)
(x-3)(x+9)=27
Let's FOIL this all out and expand. (Remember: First, Outer, Inner, Last.)
x^2 + 9x - 3x - 27
(first+ inner + outer + last)
x^2 + 9x - 3x - 27 = 27
Combine like terms, and add 27 to both sides.
x^2 + 6x - 27 + 27 = 27 + 27
x^2 + 6x = 54
Let's complete the square, because factoring doesn't work, and because it's good practice.
x^2 + 6x + ___ = 54 + ____
In the blank we will put b/2 ^2 = 6/2 ^2 = 3^2 = 9 to complete the square.
x^2 + 6x + 9 = 54 + 9
Now we've got a perfect square factor:
(x + 3)^2 = 63
sqrt(x+3)^2 = 
x + 3 = ±
x = ± - 3
Answer:
Option B
Step-by-step explanation:
Length of the rectangular sand box is given by the function,
F(x) = 3x³ + 6x - 2
Width of the sand box is represented by the function,
W(x) = 2x² - 4
Area function for the sand box will be,
Area of a rectangle = Length × Width
F(x) × W(x) = (3x³ + 6x - 2)(2x² - 4)
= 2x²(3x³ + 6x - 2) - 4(3x³ + 6x - 2)
= 6x⁵+ 12x³ - 4x²- 12x³- 24x + 8
= 6x⁵- 4x²- 24x + 8
Therefore, Area function will be represented by a polynomial degree of 5.
Option B will be the answer.
Explanation: The base of the power in the original equation becomes the base of the log. So we have 
. Next, the exponent in the original equation goes on the other side of the equation and finally, the result in the original equation goes inside the log.
So we have 
= 
which is 2³ = 8 written in logarithmic form.
