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Citrus2011 [14]
3 years ago
6

material to build a rectangular box. The length is twice the width and there is no top. What values for W and L and H will creat

e a box that encloses the maximum volume using the material you have?
Mathematics
1 answer:
Gala2k [10]3 years ago
5 0

Answer:

5id4839y47f

Step-by-step explanation:

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The volume of a cone varies jointly with the area of the base and the height. when the area of the base is
strojnjashka [21]
The volume of a cone varies jointly with the area of the base and the height of the cone.

V = kAh

where
V = volume
k = constant of proportionality
A = area of the base
h = height of the cone

The given info is for A = 27, and h = 6, then V = 54 (all using appropriate units for area, length, and volume, respectively.)

Now we can find k, the constant of proportionality.

V = kAh

54 = k * 27 * 6

k = 54/(27 * 6)

k = 1/3

The formula is

V = \dfrac{1}{3}Ah

Now we use the second set of info, the height and the volume, and we find the area of the base.

V = \dfrac{1}{3}Ah

124 = \dfrac{1}{3} \times A \times 12

124 = 4A

A = 31

Answer: the area of the base is 31 cm^2
3 0
3 years ago
Help!! I believe I need to find the L and W of browns rectangle to make macdonalds equation but I’m stuck there and need to answ
34kurt

Answer:

W man's W life W parents W pet W grand parents

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3 years ago
What is the solution to the system of equations graphed below?<br> y = -4x + 2<br> 6<br> y = x-3
Vikentia [17]

Answer:

y=14/5, x=29/5

Step-by-step explanation:

3 0
3 years ago
Can y’all help me simplify this
yKpoI14uk [10]
The simplified answer is 17.48
4 0
3 years ago
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Scores on a English test have average of 85 with standard deviation of 8. What is the probabilty of a student scoring less than
Olin [163]

Answer:47.725%

If the mean (μ) is 80, and the standard deviation (σ) is 5, then all scores between 80 and 90 would fall between 0 and 2 standard deviations above the mean.

Using the equation for Z score (Z = (X-μ)/σ) for each X value (80 and 90) then the Z scores are 0 and 2, respectively.  

Using a normal distribution table, it can be found that P(80 < z) = .5 (this is the probability that a random score would be greater than 80.  It makes sense that it is .5 or 50% because 80 is the mean.)

And the P(90 > z) = .97725.  (this is the probability that a random score would be less than 90.)

6 0
3 years ago
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