Dy/dx = (ycos(x))/(1 + y²)
(1 + y²)/y dy = cos(x) dx
(1/y + y) dy = cos(x) dx
Integrating:
ln(y) + y²/2 = sin(x) + c
ln(1) + 1/2 = sin(0) + c
c = 1/2
Thus,
ln(y) + y²/2 = sin(x) + 1/2
Answer: 28
Step-by-step explanation: All you have to do is multiply 70 by 4 and take away the zero to get your answer
Answer:
3x-4x7
Step-by-step explanation:
Answer:
See attached pictures.
Step-by-step explanation:
The sine and cosine functions have the forms: and . A is the amplitude for each function. The period is found by dividing 2π the absolute value of B or . C shifts the function up and down.
The sine function always starts and ends on the x-axis.
The cosine function always starts and ends at the y=A.
6.) The sine function starts at (0,0) then peaks at 5. Comes down to 0 and down to -5 before returning to 0.
The amplitude is 5.
The period is
7.) Here A=3 so the amplitude is 3, B is 1/2 so the period is 4π. Start at (3,0) and descend down to (2π, 0). Go back up to (4π, 3).
8.) Here A = 2 so the amplitude is A. B is 2π so the period is 1. C is 1 so the graph is shifted up a unit.
Start the graph at (0,1) and go up to (0.25,3) and down to (0.5,1) and continue downward to (0.75, -3) then back up to (1,1).