1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m².
a = 51 m, b = 37 m, c = 20 m
semiperimeter: p = (51+37+20):2 = 54 m
Area of triangle:

Rate: ₹ 3 per m².
Cost: ₹ 3•306 = ₹ 918
2. Find the area of the isosceles triangle whose perimeter is 11 cm and the base is 5 cm.
a = 5 cm
a+2b = 11 cm ⇒ 2b = 6 cm ⇒ b = 3 cm
p = 11:2 = 5.5

3. Find the area of the equilateral triangle whose each side is 8 cm.
a = b = c = 8 cm
p = (8•3):2 = 12 cm

4. The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to its base is 3 : 2. Find the area of the triangle.
a = 2x
b = 3x
2x + 2•3x = 32 cm ⇒ 8x = 32 cm ⇒ x = 4 cm ⇒ a = 8 cm, b = 12 cm
p = 32:2 = 16 cm

Answer:
okay for #2 do 3 times 3.14 divided by 4
Step-by-step explanation:
do that and tell me what you get
4x+4y..........................
Answer:
B: y = -2/3x - 10/3
Step-by-step explanation:
The point is at (-2,-2), therefore when you input -2 into the desired equation, it should yield -2 as our output. If we use the equation B, the equation becomes
-4/3 - 10/3 which is -6/3. After dividing it we get -2 as the output.
To find the line yourself we use the point slope formula
y - y1 = m(x - x1)
The line is parallel to the one on the graph so the slope or <em>m</em> is equal to -2/3
We input the coordinates we want for y1 and x1.
y - (-2) = -2/3 (x - (-2))
y + 2 = -2/3x - 4/3
y + 6/3 = -2/3x - 4/3
y = -2/3x - 10/3