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Lady bird [3.3K]
4 years ago
9

he seeds in bush bean pods are each the product of an independent fertilization event. Green seed color is dominant to white see

d color in bush beans. If a heterozygous plant with green seeds self-fertilizes, what is the probability that 6 seeds in a single pod of the progeny plant will consist of. 3 green and 3 white seeds
Mathematics
1 answer:
-BARSIC- [3]4 years ago
4 0

Answer:

THE ANSWER IS 0.055

Step-by-step explanation:

The green color seed (P) is dominated the white color seed ( Y).

Given a heterozygous plant with green seed self fertilizes .

The cross will be: PY X PY  = 1 PP: 2 PY: 1YY

Chances of having 3 white seeds out of 6 = 3/3 * 1/3 = = 1/3  .

Chances of having 3 green out of 6 = 1/3 * 1/6 = 1/18 = 0.0555

 

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