We know that the points at which the parabola intersects the x axis are
(-5,0) and (1,0)
So the extent between these two points would be the base of the triangle
lets find the length of the base using the distance formula
![\sqrt{[(-5-1)^{2}+(0-0)^{2} ]}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%5B%28-5-1%29%5E%7B2%7D%2B%280-0%29%5E%7B2%7D%20%5D%7D%20%20)
the base b=6
We will get the height of the triangle when we put x=0 in the equation
y=a(0+5)(0-1)
y=-5a
so height = -5a (we take +5a since it is the height)
We know that the area of the triangle =
× 6 × (5a) = 12
15a=12
a= 
Time taken by a regular bus to reach its destination = 3 1/4 hours
= 13/4 hours
Time taken by the express bus to make the same trip = 2 1/2 hours
= 5/2 hours
Time that can be saved by taking the express bus = (13/4) - (5/2) hours
= (13 - 10)/4 hours
= 3/4 hours
So 3/4 hours can be saved by taking the express bus rather than the regular bus. The correct option among all the options given in the question is option "C". I hope the procedure is simple enough for you to understand.
Answer:
B
Step-by-step explanation:
B, because -9.2 = -4.5, which is less than -4.12. Also, 17/4 = 4.25 is less than sqrt(20), which is 4.4721

solve for "k", to find k or the "constant of variation"
then plug k's value back to

now.... what is "p" when q = 5? well, just set "q" to 5 on the right-hand-side, and simplify, to see what "p" is
Answer:
-20 m/s.
Step-by-step explanation:
The computation of the average speed is shown below:
Given that
The initial velocity of the bus, u = 20 m/s
Aceleration of the bus, -a = 8 m/s²
time of motion, t = 5 s
Now The final velocity of the bus is
v = u + at
v = 20 + (-8 × 5)
v = 20 - 40
v = -20 m/s.