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scoray [572]
3 years ago
13

The weekly salary of a store manager includes a $30 bonus plus the number of hours the manager works multiplied by the managers

earnings per hour. Is this situation defined by a linear function?
Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
5 0

Yes. The situation is defined by a linear function.

<u>Solution:</u>

Given, The weekly salary of a store manager includes a $30 bonus plus the number of hours the manager works multiplied by the managers earnings per hour.  

Is this situation defined by a linear function?

Yes, the above given situation is defined by a linear function.

Now, let us see the linear equation for above situation

Let the number of hours worked by manager be "x", and cost per hour be "c" and total salary be "y"

Then, total salary is given as,

Total salary = $ 30 bonus + number of hours worked \times cost per hour

\rightarrow \mathrm{y}=30+\mathrm{x} \times \mathrm{c}\\\\ \rightarrow \mathrm{y}=\mathrm{c} \mathrm{x}+30

Above equation is a linear equation as "c" is constant ( cost per hour )

Hence, the given situation can be defined by linear function.

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Step-by-step explanation:

15.50n +10=72

15.50×4+10=72

62+10=72

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Help!!! Will mark Brainliest!
AleksAgata [21]

Answer:

(x-5)² + y² = 4

Step-by-step explanation:

formula of circle: (x-h)² + (y-k)² = r²  where (h,k) is coordinate of center and r is radius

center: (5 , 0)    r = 2

Equation: (x-5)² + y² = 4

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3 years ago
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natka813 [3]

Answer:

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Step-by-step explanation:

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1 year ago
Assume that a procedure yields a binomial distribution with a trial repeated n = 5 times. Use some form of technology to find th
Digiron [165]

Answer:

P(X = 0) = 0.0263

P(X = 1) = 0.1407

P(X = 2) = 0.3012

P(X = 3) = 0.3224

P(X = 4) = 0.1725

P(X = 5) = 0.0369

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 5, p = 0.517

Distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.517)^{0}.(0.483)^{5} = 0.0263

P(X = 1) = C_{5,1}.(0.517)^{1}.(0.483)^{4} = 0.1407

P(X = 2) = C_{5,2}.(0.517)^{2}.(0.483)^{3} = 0.3012

P(X = 3) = C_{5,3}.(0.517)^{3}.(0.483)^{2} = 0.3224

P(X = 4) = C_{5,4}.(0.517)^{4}.(0.483)^{1} = 0.1725

P(X = 5) = C_{5,5}.(0.517)^{5}.(0.483)^{0} = 0.0369

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3 years ago
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sergiy2304 [10]

Answer:

A. and C.

Hope this helps

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2 years ago
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