Answer:
x = (-27)/11
Step-by-step explanation:
Solve for x:
(-11 x)/54 - 1/2 = 0
Put each term in (-11 x)/54 - 1/2 over the common denominator 54: (-11 x)/54 - 1/2 = (-27)/54 - (11 x)/54:
(-27)/54 - (11 x)/54 = 0
(-27)/54 - (11 x)/54 = (-11 x - 27)/54:
(-11 x - 27)/54 = 0
Multiply both sides of (-11 x - 27)/54 = 0 by 54:
(54 (-11 x - 27))/54 = 54×0
(54 (-11 x - 27))/54 = 54/54×(-11 x - 27) = -11 x - 27:
-11 x - 27 = 54×0
0×54 = 0:
-11 x - 27 = 0
Add 27 to both sides:
(27 - 27) - 11 x = 27
27 - 27 = 0:
-11 x = 27
Divide both sides of -11 x = 27 by -11:
(-11 x)/(-11) = 27/(-11)
(-11)/(-11) = 1:
x = 27/(-11)
Multiply numerator and denominator of 27/(-11) by -1:
Answer:x = (-27)/11
The answer relies on whether the balls are different or not.
If they are not, which is almost certainly what is intended.
If they are, the perceptive is a bit different. Your
expression gives the likelihood that a particular set of j balls
goes into the last urn and the other n−j balls into the other urns.
But there are (nj) different possible sets of j balls, and each of
them the same probability of being the last insides of the last urn, so the
total probability of completing up with exactly j balls in the last
urn is if the balls are different.
See attached file for the answer.
Answer:
100,000+60,000+60
Step-by-step explanation:
Answer:
Step-by-step explanation:
I think it's 64
Answer:
probability is alway 1 or less than 1
therefore the probability is 0.125/1