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3 years ago

How is a rational number that is not an integer different from a rational number that is an integer?

2 answers:

6 0

A rational number that IS an integer would be written as a whole number, such as 21 or 999 or -2058. A rational number that ISN’T an integer would have decimals, such as 9.75 or 18.44444, as integers are whole numbers.

Andrei [34K]3 years ago

4 0

Every integer is a rational number, since each integer n can be written in the form n/1. For example 5 = 5/1 and thus 5 is a rational number. However, numbers like 1/2, 45454737/2424242, and -3/7 are also rational, since they are fractions whose numerator and denominator are integers.

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A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago

Jenna has a piece of paper that is 84 square inches in area. It is 21/2 inches long. What is the length of the piece of paper in

Lerok [7]

Answer:

Step-by-step explanation:

Area = 84sqaure inch

Width = 2 1/2inch = 5/2inch

Area = l × width

So: 84 = l × 5/2

168 = 5l

l =>168/5

l = 33 3/5

7 0

3 years ago

Actually help on this one plz

user100 [1]

Given the fact that AB≈AD, then 35 is also the angle measure of ADB. The sum of the angles of a triangle =180. 35+35=70. 180-70=110

X=110°

4 0

3 years ago

Which graph best represents the solution to the following pair of equations?

olasank [31]

Answer:

where are the graphs?

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What’s the answer ASAP

Oksi-84 [34.3K]

Answer:

none

Step-by-step explanation:

38×2=76

43×2=86

45×2=90

4 0

3 years ago