Answer: he would have $343.47 after 2 years.
Step-by-step explanation:
if he leaves his interest from the first year in the bank, we would assume that his interest was compounded. We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = $300
r = 7% = 7/100 = 0.07
n = 1 because it was compounded once in a year.
t = 2 years
Therefore,.
A = 300(1 + 0.07/1)^1 × 2
A = 300(1.07)^2
A = $343.47
Answer:
I think you need 8 papers
Because the board is 6 meters in length and each section is a meter long. Using fractions, one section of the 6 meter board is 1/6. 1 can go into 6, six times. So, you end up with 6 sections that are each 1 meter long.
X² + 4x = 96
Subtract 96 from both sides to get the equation equal to zero:
x² + 4x - 96 = 0
We can solve for x either by factoring or by using the Quadratic Formula. Let's attempt to factor first. To factor, find two numbers whose sum is 4 and whose product is -96. Since 96 is negative, the pair will be one positive and one negative (a positive times a negative is always negative). Let's start listing addends of 4 and calculating their product.
12 + (-8) = 4; 12 × (-8) = -96
The pair is 12 and -8. The factored polynomial is (x + 12)(x - 8). To find x, find the zeros.
x + 12 = 0
x = -12
x - 8 = 0
x = 8
Answer:
x = -12 and x = 8
Answer:
After using distributive property to remove the parentheses
we get ![10u-20](https://tex.z-dn.net/?f=10u-20)
Step-by-step explanation:
We need to use distributive property to remove the parentheses 10(u-2)
According to distributive property of multiplication over subtraction:
![a(b-c)=ab-ac](https://tex.z-dn.net/?f=a%28b-c%29%3Dab-ac)
Using the above distributive property to solve the question. Multiply 10 with terms inside the bracket and solving:
![10(u-2)\\=10u-10*2\\=10u-20](https://tex.z-dn.net/?f=10%28u-2%29%5C%5C%3D10u-10%2A2%5C%5C%3D10u-20)
So, After using distributive property to remove the parentheses
we get ![10u-20](https://tex.z-dn.net/?f=10u-20)