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Blizzard [7]
3 years ago
10

Which equation represents the relationship 3 more than a number is 7

Mathematics
1 answer:
klasskru [66]3 years ago
6 0

Answer:

3+n=7

Step-by-step explanation:

I used as as number

Because there is 3 more than the number, we add 3

3+n is 7 and is means =, so 3+n=7

Hope this helps

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s344n2d4d5 [400]
Pretty sure that's right.

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2 years ago
if a sequence is defined recursively by f(0)=4 and f(n+1)= -3f(n+1)=-3f(n)+1 for n≥0, then f(3) is equal to? DESPERATELY NEED HE
muminat

f(3) is equal to -101.

<u>Step-by-step explanation</u>:

  • The sequence is followed by f(0)=4
  • The given expression is f(n+1)= -3f(n)+1

Put n=0,

f(0+1)= -3f(0)+1

f(1)= -3(4)+1

f(1)= -12+1 = -11

Put n=1,

f(1+1)= -3f(1)+1

f(2)= -3(-11)+1

f(2)= 33+1 = 34

Put n=2,

f(2+1)= -3f(2)+1

f(3)= -3(34)+1

f(3)= -102+1

f(3)= -101

5 0
3 years ago
Evaluate the surface integral. s y ds, s is the helicoid with vector equation r(u, v) = u cos(v), u sin(v), v , 0 ≤ u ≤ 6, 0 ≤ v
Juliette [100K]

Compute the surface element:

\mathrm dS=\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv

\vec r(u,v)=(u\cos v,u\sin v,v)\implies\begin{cases}\vec r_u=(\cos v,\sin v,0)\\\vec r_v=(-u\sin v,u\cos v,1)\end{cases}

\|\vec r_u\times\vec r_v\|=\sqrt{\sin^2v+(-\cos v)^2+u^2}=\sqrt{1+u^2}

So the integral is

\displaystyle\iint_Sy\,\mathrm dS=\int_0^\pi\int_0^6u\sin v\sqrt{1+u^2}\,\mathrm du\,\mathrm dv

=\displaystyle\left(\int_0^\pi\sin v\,\mathrm dv\right)\left(\int_0^6u\sqrt{1+u^2}\,\mathrm du\right)

=\dfrac23(37^{3/2}-1)

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3 years ago
2,750 milliliters into gallons.
yan [13]

Answer:

2,750 milliliters into gallons=0.72647314

Step-by-step explanation:

4 0
1 year ago
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What is the range of the relation below?
True [87]

Answer:

D.

Step-by-step explanation:

because the lowest y is -3 and the highest is 2

8 0
3 years ago
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