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riadik2000 [5.3K]
4 years ago
14

What are other ways to write 8.517?

Mathematics
2 answers:
tia_tia [17]4 years ago
6 0
8.52? I think.....maybe
Murrr4er [49]4 years ago
4 0
Word form: Eight and five hundred seventeen thousandths.

Expanded form: (8)+(0.5)+(0.01)+(0.007)

Round up: 8.520
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3 years ago
Enter your answer and show all the steps that you use to solve this problem in the space provided. Simplify ( 6 x − 2 ) 2 ( 0 .
den301095 [7]

Answer:

\frac{9x^6}{4}-\frac{3x^5}{2}+\frac{x^4}{4}

Step-by-step explanation:

We want to simplify:

(6x-2)^2(0.5x)^4

We expand to get:

(36x^2-24x+4)*\frac{x^4}{16}

We expand further to get:

\frac{9x^6}{4}-\frac{3x^5}{2}+\frac{x^4}{4}

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3 years ago
Suppose you needed $ 22 comma 000$22,000 to maintain a particular standard of living in 19781978. How much would you have needed
wlad13 [49]
Sorry i dont know this is kind of tricky
5 0
3 years ago
A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday's mail. In actuali
Dominik [7]

Answer:

y                 0             1              2          3

P(Y=y)   0.0676   0.3549   0.3875   0.19

Step-by-step explanation:

P(Wed) = 0.26

P(Thurs) = 0.39

P(Fri) = 0.25

P(Sat) = 0.10

Y = No. of days beyond Wednesday it takes for both magazines to arrive i.e. 0,1,2,3

Y=0 means the magazines will arrive on Wednesday

Y=1 means the magazines will arrive till Thursday

Y=2 means the magazines will arrive till Friday

Y=3 means the magazines will arrive till Saturday

The possible combinations for Y are

Y(W,W) Y(W,T) Y(W,F) Y(W,S)

Y(T,W) Y(T,T) Y(T,F) Y(T,S)

Y(F,W) Y(F,T) Y(F,F) Y(F,S)

Y(S,W) Y(S,T) Y(S,F) Y(S,S)

So, we can classify these possible outcomes as Y=0,1,2,3.

Y(0) = Y(W,W) (both magazines take 0 days to arrive beyond Wednesday)

Y(1) = Y(W,T), Y(T,T), Y(T,W) (both magazines take 1 day to arrive beyond Wednesday)

Y(2) = Y(W,F), Y(T,F), Y(F,F) Y(F,W) Y(F,T) (both magazines arrive till Friday)

Y(3) = Y(W,S), Y(T,S), Y(F,S), Y(S,W), Y(S,T), Y(S,F), Y(S,S) (both magazines arrive till Saturday)

To calculate the PMF, we need to calculate the probability for each of the points in Y(0,1,2,3).

Y(0) = Y(W,W)

       = 0.26 x 0.26

Y(0) = 0.0676

Y(1) = Y(W,T) + Y(T,T) + Y(T,W)

      = (0.26 x 0.39) + (0.39 x 0.39) + (0.39 x 0.26)

      = 0.1014 + 0.1521 + 0.1014

Y(1) = 0.3549

Y(2) = Y(W,F) + Y(T,F) + Y(F,F) + Y(F,W) + Y(F,T)

  =(0.26 x 0.25) + (0.39 x 0.25) + (0.25 x 0.25) + (0.25 x 0.26) + (0.25 x 0.39)

  = 0.065 + 0.0975 + 0.0625 + 0.065 + 0.0975

Y(2) = 0.3875

Y(3) = Y(W,S) + Y(T,S) + Y(F,S) + Y(S,W) + Y(S,T) + Y(S,F) + Y(S,S)

      = (0.26 x 0.10) + (0.39 x 0.10) + (0.25 x 0.10) + (0.10 x 0.26) + (0.10 x 0.39) + (0.10 x 0.25) + (0.10 x 0.10)

       = 0.026 + 0.039 + 0.025 + 0.026 + 0.039 + 0.025 + 0.010

Y(3) = 0.19

y                 0             1              2          3

P(Y=y)   0.0676   0.3549   0.3875   0.19

The PMF plot is attached as a photo here.

7 0
4 years ago
Four students share 7 sandwiches equally. How much of a sandwich does each student get
garri49 [273]

Answer: 1.75

7 ÷ 4 = \frac{7}{4} = 1.75

3 0
3 years ago
Read 2 more answers
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