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ZanzabumX [31]
2 years ago
7

How much of the circle is shaded? Write your answer as a fraction in simplest form. 1/3 and 1/7

Mathematics
1 answer:
Ludmilka [50]2 years ago
6 0

Answer:

11/21

Step-by-step explanation:

1/3=7/21

1/7=3/21

(7+3)/21=10/21

21/21-10/21=11/21

Thus 11/21 of the circle is shaded.

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Arrange these numbers in order from least to greatest <br><br> 1/2, 0,-2,1
Andru [333]

Answer:

-2, 0, 1/2, 1

Step-by-step explanation:

6 0
3 years ago
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PLZZZ HELPPPP Assume line q is parallel to line m. Choose from the drop-down menus to solve for m∠6​​
Vikentia [17]

Answer:

1= 75 2= 60 3=180 4=45 5= vertical angles 6=45

Step-by-step explanation:

All we have to do is use supplimentary angles

For example angle 1

105+angle 1=180

angle one = 75 degrees

120+angle 2=180

angle two= 60 degrees

There 180 degreees in a triagle.

So angle 1 + angle 2+ angle 7= 180

75+60+angle 7=180

angle 7= 45 degrees

And since 6 and 7 are vertical angles, angle 6 is also 45 degrees.

8 0
2 years ago
Define the axis of symmetry, vertex, focus and directrix for
Papessa [141]

Answer:

  see attached

Step-by-step explanation:

The equation is in the form ...

  4p(y -k) = (x -h)^2 . . . . . (h, k) is the vertex; p is the focus-vertex distance

Comparing this to your equation, we see ...

  p = 4, (h, k) = (3, 4)

p > 0, so the parabola opens upward. The vertex is on the axis of symmetry. That axis has the equation x=x-coordinate of vertex. This tells you ...

  vertex: (3, 4)

  axis of symmetry: x = 3

  focus: (3, 8) . . . . . 4 units up from vertex

  directrix: y = 0 . . . horizontal line 4 units down from vertex

8 0
2 years ago
The scale drawing for Lydia’s room is drawn so that 1 cm = 1 ft. If the scale drawing shows the area of her room to be 51 square
butalik [34]
Should be 51 ft. sonve 1 cm = 1 ft
3 0
3 years ago
Can somebody tell me if I did it right I’m not sure how I’m supposed to find the distance?
Salsk061 [2.6K]

Answer:

6.4 units

Step-by-step explanation:

Use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d=\sqrt{(8-3)^2+(-3-(-7))^2}

d=\sqrt{(5)^2+(4)^2}

d=\sqrt{25+16}

d=\sqrt{41}

d=6.4

Therefore, the distance between (3,-7) and (8,-3) is 6.4 units

Hopefully, this was helpful!

5 0
3 years ago
Read 2 more answers
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