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IrinaK [193]
3 years ago
6

Could somebody please help me with this ( and please show your work )

Mathematics
1 answer:
Serga [27]3 years ago
3 0

Answer:

14

Step-by-step explanation:

7x4 = 28/2 = 14

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In a given year there is a 3% chance you will get in a small accident costing around $2000 and 0.1% chance you will get in a maj
Wittaler [7]

Answer:

$475

Step-by-step explanation:

There are 3 possible accident in this question

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0.1% chance of losing $150,000

96.9% chance of losing $0

Then the expected value that you will lose is:

3%*  $2000  + (0.1% *  $15000) + (96.9% * $0)= $75

Profit made by subtracting the price with the lose. If the company want average profit $400, the charge should be:

average profit = premium price - average lose

premium price= average profit + average lose

premium price= $400 + $75 = $475

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4 years ago
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Montano1993 [528]

Answer:

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Step-by-step explanation:

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3 years ago
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vlabodo [156]
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8 0
2 years ago
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URGENT NEED HELP FAST LINKS WILL BE REPORTED
dolphi86 [110]

Answer:

model B is shaded to represent 37.5%

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3 years ago
Evaluate the limit of tan 4x/ 4tan3x​
Brut [27]

Answer:

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Step-by-step explanation:

The ratio is undefined at x=0, so we presume that's where we're interested in the limit. Both numerator and denominator are zero at x=0, so L'Hôpital's rule applies. According to that rule, we replace numerator and denominator with their respective derivatives.

  \displaystyle\lim\limits_{x\to 0}\dfrac{\tan{(4x)}}{4\tan{(3x)}}=\lim\limits_{x\to 0}\dfrac{\tan'{(4x)}}{4\tan'{(3x)}}=\lim\limits_{x\to 0}\dfrac{4\sec{(4x)^2}}{12\sec{(3x)^2}}=\dfrac{4}{12}\\\\\boxed{\lim\limits_{x\to 0}\dfrac{\tan{(4x)}}{4\tan{(3x)}}=\dfrac{1}{3}}

6 0
3 years ago
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